Convert Pound Foot per Square Second to Joules per Centimeter
Use this free online force converter to change pound foot per square second into joules per centimeter instantly. Type in the pound foot per square second value, and the equivalent joules per centimeter is calculated for you in real time.
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Enter your inputs, and the result is calculated in real-time.
Pound Foot per Square Second
Joules per Centimeter
How to use this Pound Foot per Square Second to Joules per Centimeter Converter 🤔
Follow these steps to convert given Pound Foot per Square Second value from Pound Foot per Square Second units to Joules per Centimeter units.
Enter the input Pound Foot per Square Second value in the text field.
The given Pound Foot per Square Second is converted to Joules per Centimeter in realtime ⌚ using the formula, and displayed under the Joules per Centimeter label.
You may copy the resulting Joules per Centimeter value using the Copy button.
Formula
To convert given force from Pound Foot per Square Second to Joules per Centimeter, use the following formula.
Joules per Centimeter = Pound Foot per Square Second * 13.825495437599988
Calculation
Calculation will be done after you enter a valid input.
Pound Foot per Square Second
Pound foot per square second is a unit used to describe force in the FPS system. It is sometimes used in older engineering contexts or for specialized calculations.
Joules per Centimeter
Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science.
{
"conversion": "pound-foot-per-square-second-joule-per-centimeter",
"x_slug": "pound-foot-per-square-second",
"y_slug": "joule-per-centimeter",
"x": "lbf·ft/s²",
"y": "J/cm",
"x_desc": "Pound Foot per Square Second",
"y_desc": "Joules per Centimeter",
"category": "Force",
"symbol": "m",
"formula": "x * 13.825495437599988",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a system applying 250 pound-foot-per-square-second of force to rotate a wheel.<br>Convert this force from pound-foot-per-square-second to Joules per Centimeter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of wheel in pound foot per square second is:</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = 250</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from pound foot per square second to joules per centimeter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>Force<sub>(Pound Foot per Square Second)</sub></span> × 13.825495437599988</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of wheel, <strong>Force<sub>(Pound Foot per Square Second)</sub> = 250</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>250</span> × 13.825495437599988</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 3456.3739</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>250 lbf·ft/s²</strong> is equal to <strong>3456.3739 J/cm</strong>.</p>\n <p>The force of wheel is <strong>3456.3739 J/cm</strong>, in joules per centimeter.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a pendulum experiencing 100 pound-foot-per-square-second of force as it swings.<br>Convert this force from pound-foot-per-square-second to Joules per Centimeter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of pendulum in pound foot per square second is:</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = 100</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from pound foot per square second to joules per centimeter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>Force<sub>(Pound Foot per Square Second)</sub></span> × 13.825495437599988</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of pendulum, <strong>Force<sub>(Pound Foot per Square Second)</sub> = 100</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>100</span> × 13.825495437599988</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 1382.5495</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>100 lbf·ft/s²</strong> is equal to <strong>1382.5495 J/cm</strong>.</p>\n <p>The force of pendulum is <strong>1382.5495 J/cm</strong>, in joules per centimeter.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"y_long_desc": "Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science.",
"x_long_desc": "Pound foot per square second is a unit used to describe force in the FPS system. It is sometimes used in older engineering contexts or for specialized calculations."
}
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