Convert Gram-Force to Pound Foot per Square Second
Use this free online force converter to change gram-force into pound foot per square second instantly. Type in the gram-force value, and the equivalent pound foot per square second is calculated for you in real time.
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Enter your inputs, and the result is calculated in real-time.
Gram-Force
Pound Foot per Square Second
How to use this Gram-Force to Pound Foot per Square Second Converter 🤔
Follow these steps to convert given Gram-Force value from Gram-Force units to Pound Foot per Square Second units.
Enter the input Gram-Force value in the text field.
The given Gram-Force is converted to Pound Foot per Square Second in realtime ⌚ using the formula, and displayed under the Pound Foot per Square Second label.
You may copy the resulting Pound Foot per Square Second value using the Copy button.
Formula
To convert given force from Gram-Force to Pound Foot per Square Second, use the following formula.
Pound Foot per Square Second = Gram-Force * 0.07093163528396954
Calculation
Calculation will be done after you enter a valid input.
Gram-Force
Gram-force (gf) is the force exerted by the weight of one gram under standard gravity. It’s a small unit of force often used in applications like measuring the tension of lightweight objects or precision instruments. Although it’s not an SI unit, gram-force provides an intuitive way to represent small forces.
Pound Foot per Square Second
Pound foot per square second is a unit used to describe force in the FPS system. It is sometimes used in older engineering contexts or for specialized calculations.
{
"conversion": "gram-force-pound-foot-per-square-second",
"x_slug": "gram-force",
"y_slug": "pound-foot-per-square-second",
"x": "gf",
"y": "lbf·ft/s²",
"x_desc": "Gram-Force",
"y_desc": "Pound Foot per Square Second",
"category": "Force",
"symbol": "m",
"formula": "x * 0.07093163528396954",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a small object weighing 300 grams, applying a force of 300 gram-force.<br>Convert this force from gram-force to Pound Foot per Square Second.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of object in gram-force is:</p>\n <p class=\"step\"><span>Force<sub>(Gram-Force)</sub></span> = 300</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from gram-force to pound foot per square second is:</p>\n <p class=\"formula step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>Force<sub>(Gram-Force)</sub></span> × 0.07093163528396954</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of object, <strong>Force<sub>(Gram-Force)</sub> = 300</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>300</span> × 0.07093163528396954</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = 21.2795</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>300 gf</strong> is equal to <strong>21.2795 lbf·ft/s²</strong>.</p>\n <p>The force of object is <strong>21.2795 lbf·ft/s²</strong>, in pound foot per square second.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a feather that weighs 50 gram-force.<br>Convert this force from gram-force to Pound Foot per Square Second.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of feather in gram-force is:</p>\n <p class=\"step\"><span>Force<sub>(Gram-Force)</sub></span> = 50</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from gram-force to pound foot per square second is:</p>\n <p class=\"formula step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>Force<sub>(Gram-Force)</sub></span> × 0.07093163528396954</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of feather, <strong>Force<sub>(Gram-Force)</sub> = 50</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>50</span> × 0.07093163528396954</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = 3.5466</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>50 gf</strong> is equal to <strong>3.5466 lbf·ft/s²</strong>.</p>\n <p>The force of feather is <strong>3.5466 lbf·ft/s²</strong>, in pound foot per square second.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"x_long_desc": "Gram-force (gf) is the force exerted by the weight of one gram under standard gravity. It’s a small unit of force often used in applications like measuring the tension of lightweight objects or precision instruments. Although it’s not an SI unit, gram-force provides an intuitive way to represent small forces.",
"y_long_desc": "Pound foot per square second is a unit used to describe force in the FPS system. It is sometimes used in older engineering contexts or for specialized calculations."
}
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