Use this free online force converter to change metric ton-force into joules per centimeter instantly. Type in the metric ton-force value, and the equivalent joules per centimeter is calculated for you in real time.
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Metric Ton-Force
Joules per Centimeter
How to use this Metric Ton-Force to Joules per Centimeter Converter 🤔
Follow these steps to convert given Metric Ton-Force value from Metric Ton-Force units to Joules per Centimeter units.
Enter the input Metric Ton-Force value in the text field.
The given Metric Ton-Force is converted to Joules per Centimeter in realtime ⌚ using the formula, and displayed under the Joules per Centimeter label.
You may copy the resulting Joules per Centimeter value using the Copy button.
Formula
To convert given force from Metric Ton-Force to Joules per Centimeter, use the following formula.
Joules per Centimeter = Metric Ton-Force * 9.806650000000271e+5
Calculation
Calculation will be done after you enter a valid input.
Metric Ton-Force
Ton-force represents the force exerted by the weight of one metric ton under standard gravity. It’s used for measuring very large forces, such as the force exerted by a building structure or a piece of heavy machinery. It’s a convenient way to represent massive loads encountered in engineering and construction.
Joules per Centimeter
Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science.
{
"conversion": "ton-force-joule-per-centimeter",
"x_slug": "ton-force",
"y_slug": "joule-per-centimeter",
"x": "tf",
"y": "J/cm",
"x_desc": "Metric Ton-Force",
"y_desc": "Joules per Centimeter",
"category": "Force",
"symbol": "m",
"formula": "x * 9.806650000000271e+5",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a large truck exerting a force of 10 ton-force on the road.<br>Convert this force from ton-force to Joules per Centimeter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of truck on the road in metric ton-force is:</p>\n <p class=\"step\"><span>Force<sub>(Metric Ton-Force)</sub></span> = 10</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from metric ton-force to joules per centimeter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>Force<sub>(Metric Ton-Force)</sub></span> × 9.806650000000271e+5</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of truck on the road, <strong>Force<sub>(Metric Ton-Force)</sub> = 10</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>10</span> × 9.806650000000271e+5</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 9806650</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>10 tf</strong> is equal to <strong>9806650 J/cm</strong>.</p>\n <p>The force of truck on the road is <strong>9806650 J/cm</strong>, in joules per centimeter.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a construction machine that applies 20 ton-force to move debris.<br>Convert this force from ton-force to Joules per Centimeter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of machine in metric ton-force is:</p>\n <p class=\"step\"><span>Force<sub>(Metric Ton-Force)</sub></span> = 20</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from metric ton-force to joules per centimeter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>Force<sub>(Metric Ton-Force)</sub></span> × 9.806650000000271e+5</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of machine, <strong>Force<sub>(Metric Ton-Force)</sub> = 20</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>20</span> × 9.806650000000271e+5</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 19613300</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>20 tf</strong> is equal to <strong>19613300 J/cm</strong>.</p>\n <p>The force of machine is <strong>19613300 J/cm</strong>, in joules per centimeter.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"x_long_desc": "Ton-force represents the force exerted by the weight of one metric ton under standard gravity. It’s used for measuring very large forces, such as the force exerted by a building structure or a piece of heavy machinery. It’s a convenient way to represent massive loads encountered in engineering and construction.",
"y_long_desc": "Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science."
}
ConvertOnline