Convert Kilopound-Force to Pound Foot per Square Second
Use this free online force converter to change kilopound-force into pound foot per square second instantly. Type in the kilopound-force value, and the equivalent pound foot per square second is calculated for you in real time.
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Kilopound-Force
Pound Foot per Square Second
How to use this Kilopound-Force to Pound Foot per Square Second Converter 🤔
Follow these steps to convert given Kilopound-Force value from Kilopound-Force units to Pound Foot per Square Second units.
Enter the input Kilopound-Force value in the text field.
The given Kilopound-Force is converted to Pound Foot per Square Second in realtime ⌚ using the formula, and displayed under the Pound Foot per Square Second label.
You may copy the resulting Pound Foot per Square Second value using the Copy button.
Formula
To convert given force from Kilopound-Force to Pound Foot per Square Second, use the following formula.
Pound Foot per Square Second = Kilopound-Force * 3.2174048556389036e+4
Calculation
Calculation will be done after you enter a valid input.
Kilopound-Force
Kilopound-force (kipf) is another term for kip-force, which represents 1,000 pounds of force. It is a unit frequently used in structural analysis and design in engineering to simplify large force calculations.
Pound Foot per Square Second
Pound foot per square second is a unit used to describe force in the FPS system. It is sometimes used in older engineering contexts or for specialized calculations.
{
"conversion": "kilopound-force-pound-foot-per-square-second",
"x_slug": "kilopound-force",
"y_slug": "pound-foot-per-square-second",
"x": "kipf",
"y": "lbf·ft/s²",
"x_desc": "Kilopound-Force",
"y_desc": "Pound Foot per Square Second",
"category": "Force",
"symbol": "m",
"formula": "x * 3.2174048556389036e+4",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider an engine producing 1 kilopound-force to propel an aircraft.<br>Convert this force from kilopound-force to Pound Foot per Square Second.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of aircraft in kilopound-force is:</p>\n <p class=\"step\"><span>Force<sub>(Kilopound-Force)</sub></span> = 1</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from kilopound-force to pound foot per square second is:</p>\n <p class=\"formula step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>Force<sub>(Kilopound-Force)</sub></span> × 3.2174048556389036e+4</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of aircraft, <strong>Force<sub>(Kilopound-Force)</sub> = 1</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>1</span> × 3.2174048556389036e+4</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = 32174.0486</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>1 kipf</strong> is equal to <strong>32174.0486 lbf·ft/s²</strong>.</p>\n <p>The force of aircraft is <strong>32174.0486 lbf·ft/s²</strong>, in pound foot per square second.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a machine applying 5 kilopound-force to move heavy equipment.<br>Convert this force from kilopound-force to Pound Foot per Square Second.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of machine in kilopound-force is:</p>\n <p class=\"step\"><span>Force<sub>(Kilopound-Force)</sub></span> = 5</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from kilopound-force to pound foot per square second is:</p>\n <p class=\"formula step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>Force<sub>(Kilopound-Force)</sub></span> × 3.2174048556389036e+4</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of machine, <strong>Force<sub>(Kilopound-Force)</sub> = 5</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>5</span> × 3.2174048556389036e+4</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = 160870.2428</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>5 kipf</strong> is equal to <strong>160870.2428 lbf·ft/s²</strong>.</p>\n <p>The force of machine is <strong>160870.2428 lbf·ft/s²</strong>, in pound foot per square second.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
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],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
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[
"dyne",
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"dyn"
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[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
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[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"x_long_desc": "Kilopound-force (kipf) is another term for kip-force, which represents 1,000 pounds of force. It is a unit frequently used in structural analysis and design in engineering to simplify large force calculations.",
"y_long_desc": "Pound foot per square second is a unit used to describe force in the FPS system. It is sometimes used in older engineering contexts or for specialized calculations."
}
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