Convert Pound Foot per Square Second to Kilopound-Force
Use this free online force converter to change pound foot per square second into kilopound-force instantly. Type in the pound foot per square second value, and the equivalent kilopound-force is calculated for you in real time.
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Pound Foot per Square Second
Kilopound-Force
How to use this Pound Foot per Square Second to Kilopound-Force Converter 🤔
Follow these steps to convert given Pound Foot per Square Second value from Pound Foot per Square Second units to Kilopound-Force units.
Enter the input Pound Foot per Square Second value in the text field.
The given Pound Foot per Square Second is converted to Kilopound-Force in realtime ⌚ using the formula, and displayed under the Kilopound-Force label.
You may copy the resulting Kilopound-Force value using the Copy button.
Formula
To convert given force from Pound Foot per Square Second to Kilopound-Force, use the following formula.
Kilopound-Force = Pound Foot per Square Second * 3.1080950171607255e-5
Calculation
Calculation will be done after you enter a valid input.
Pound Foot per Square Second
Pound foot per square second is a unit used to describe force in the FPS system. It is sometimes used in older engineering contexts or for specialized calculations.
Kilopound-Force
Kilopound-force (kipf) is another term for kip-force, which represents 1,000 pounds of force. It is a unit frequently used in structural analysis and design in engineering to simplify large force calculations.
{
"conversion": "pound-foot-per-square-second-kilopound-force",
"x_slug": "pound-foot-per-square-second",
"y_slug": "kilopound-force",
"x": "lbf·ft/s²",
"y": "kipf",
"x_desc": "Pound Foot per Square Second",
"y_desc": "Kilopound-Force",
"category": "Force",
"symbol": "m",
"formula": "x * 3.1080950171607255e-5",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a system applying 250 pound-foot-per-square-second of force to rotate a wheel.<br>Convert this force from pound-foot-per-square-second to Kilopound-Force.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of wheel in pound foot per square second is:</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = 250</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from pound foot per square second to kilopound-force is:</p>\n <p class=\"formula step\"><span>Force<sub>(Kilopound-Force)</sub></span> = <span>Force<sub>(Pound Foot per Square Second)</sub></span> × 3.1080950171607255e-5</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of wheel, <strong>Force<sub>(Pound Foot per Square Second)</sub> = 250</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Kilopound-Force)</sub></span> = <span>250</span> × 3.1080950171607255e-5</p>\n <p class=\"step\"><span>Force<sub>(Kilopound-Force)</sub></span> = 0.00777023754</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>250 lbf·ft/s²</strong> is equal to <strong>0.00777023754 kipf</strong>.</p>\n <p>The force of wheel is <strong>0.00777023754 kipf</strong>, in kilopound-force.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a pendulum experiencing 100 pound-foot-per-square-second of force as it swings.<br>Convert this force from pound-foot-per-square-second to Kilopound-Force.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of pendulum in pound foot per square second is:</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = 100</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from pound foot per square second to kilopound-force is:</p>\n <p class=\"formula step\"><span>Force<sub>(Kilopound-Force)</sub></span> = <span>Force<sub>(Pound Foot per Square Second)</sub></span> × 3.1080950171607255e-5</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of pendulum, <strong>Force<sub>(Pound Foot per Square Second)</sub> = 100</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Kilopound-Force)</sub></span> = <span>100</span> × 3.1080950171607255e-5</p>\n <p class=\"step\"><span>Force<sub>(Kilopound-Force)</sub></span> = 0.00310809502</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>100 lbf·ft/s²</strong> is equal to <strong>0.00310809502 kipf</strong>.</p>\n <p>The force of pendulum is <strong>0.00310809502 kipf</strong>, in kilopound-force.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
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[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"y_long_desc": "Kilopound-force (kipf) is another term for kip-force, which represents 1,000 pounds of force. It is a unit frequently used in structural analysis and design in engineering to simplify large force calculations.",
"x_long_desc": "Pound foot per square second is a unit used to describe force in the FPS system. It is sometimes used in older engineering contexts or for specialized calculations."
}
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