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Free Fall Calculator

Enter any three inputs to calculate the other two values


\( v = u + g \cdot t \)
\( h = u \cdot t + \frac{1}{2} g \cdot t^2 \)

u : m/s
t : s
g : m/s²
v : m/s
h : m





How to use this Free Fall Calculator 🤔

  1. There are input fields for Initial velocity \((u)\), Time of fall \((t)\), Acceleration due to gravity \((g)\), Final velocity \((v)\), and Height \((h)\). Enter any three inputs to calculate the other two values.
  2. The calculator uses the \( v = u + g \cdot t \)
    \( h = u \cdot t + \frac{1}{2} g \cdot t^2 \) formula, substitues given values, and calcuates the missing value.
  3. The missing value is calcuated and displayed in the input field. Also, the caculation is displayed under the input section.

What is Free Fall?

Free fall refers to the motion of an object falling under the influence of gravity alone, without any air resistance. The key parameters in free fall are time of fall (t), final velocity (v), height (h), initial velocity (u), and the acceleration due to gravity (g).

Calculating Final Velocity and Height

The final velocity of an object in free fall is calculated using the formula:

\( v = u + g \cdot t \).

The height from which the object falls is calculated using the formula:

\( h = u \cdot t + \frac{1}{2} g \cdot t^2 \).


Input and Output Combinations of the Free Fall Calculator

Here are the input combinations available for the calculator, along with the formulas it uses to calculate the corresponding outputs.

Calculator InputsSet #1
  • t Time of fall
  • u Initial velocity
  • g Acceleration due to gravity

For these given inputs,

Outputs, Formulas

We calculate the following outputs:

  • Final velocity\(v = \)\( u + g \cdot t \)
  • Height\(h = \)\( u \cdot t + \frac{1}{2} g \cdot t ^2 \)
2 Examples
Calculator InputsSet #2
  • v Final velocity
  • u Initial velocity
  • g Acceleration due to gravity

For these given inputs,

Outputs, Formulas

We calculate the following outputs:

  • Time of fall\(t = \)\( \frac{ v - u }{ g } \)
  • Height\(h = \)\( u \cdot \frac{ v - u }{ g } + \frac{1}{2} g \cdot \left( \frac{ v - u }{ g } \right)^2 \)
1 Example
Calculator InputsSet #3
  • h Height
  • u Initial velocity
  • g Acceleration due to gravity

For these given inputs,

Outputs, Formulas

We calculate the following outputs:

  • Time of fall\(t = \)\( \frac{ - u + \sqrt{ u ^2 + 2 g h } }{ g } \)
  • Final velocity\(v = \)\( \sqrt{ u ^2 + 2 g h } \)
1 Example
Calculator InputsSet #4
  • v Final velocity
  • t Time of fall
  • g Acceleration due to gravity

For these given inputs,

Outputs, Formulas

We calculate the following outputs:

  • Initial velocity\(u = \)\( v - g \cdot t \)
  • Height\(h = \)\(( v - g \cdot t ) \cdot t + \frac{1}{2} g \cdot t ^2 \)
1 Example
Calculator InputsSet #5
  • h Height
  • t Time of fall
  • g Acceleration due to gravity

For these given inputs,

Outputs, Formulas

We calculate the following outputs:

  • Initial velocity\(u = \)\( \frac{ h - \frac{1}{2} g \cdot t ^2 }{ t } \)
  • Final velocity\(v = \)\( \frac{ h + \frac{1}{2} g \cdot t^2 }{ t } \)
Calculator InputsSet #6
  • h Height
  • v Final velocity
  • g Acceleration due to gravity

For these given inputs,

Outputs, Formulas

We calculate the following outputs:

  • Time of fall\(t = \)\( \frac{ v + \sqrt{ v ^2 - 2 g h } }{ g } \)
  • Initial velocity\(u = \)\( v - g \cdot t \)
Calculator InputsSet #7
  • t Time of fall
  • u Initial velocity
  • h Height

For these given inputs,

Outputs, Formulas

We calculate the following outputs:

  • Acceleration due to gravity\(g = \)\( \frac{ 2 \cdot ( h - u \cdot t ) }{ t ^2 } \)
  • Final velocity\(v = \)\( u + g \cdot t \)


Examples

1

Consider that a person dropped an object from the top of a building with an initial velocity of 4 m/s. The object travelled for 10 s before touching the ground.
What is the final velocity of object, and height of the building?

Answer

Given:

  • Time of fall, t = 10 s
  • Initial velocity, u = 4 m/s
  • Acceleration due to gravity, g = 9.81 m/s²

Calculating final velocity (v)...

\( v = \) \( u + g \cdot t \)

\( v = \) \(4+9.81\times10\)

\( v = \) 102.1 m/s

Calculating height (h)...

\( h = \) \( u \cdot t + \frac{1}{2} g \cdot t ^2 \)

\( h = \) \(4\times10+ \frac{1}{2} \times9.81\times10^2 \)

\( h = \) 530.5 m

2

Consider that a person dropped an object from the top of a building with an initial velocity of 0 m/s. The object travelled for 2 s before touching the ground.
What is the final velocity of object, and height of the building?

Answer

Given:

  • Time of fall, t = 2 s
  • Initial velocity, u = 0 m/s
  • Acceleration due to gravity, g = 9.81 m/s²

Calculating final velocity (v)...

\( v = \) \( u + g \cdot t \)

\( v = \) \(0+9.81\times2\)

\( v = \) 19.62 m/s

Calculating height (h)...

\( h = \) \( u \cdot t + \frac{1}{2} g \cdot t ^2 \)

\( h = \) \(0\times2+ \frac{1}{2} \times9.81\times2^2 \)

\( h = \) 19.62 m

3

Consider that a bird dropped a toy from top of an electric pole. The initial velocity of the toy is 4 m/s. The toy reached a final velocity of 20 m/s before touching the ground.
What is the height of the pole, and time taken by the toy to reach the ground?

Answer

Given:

  • Final velocity, v = 20 m/s
  • Initial velocity, u = 4 m/s
  • Acceleration due to gravity, g = 9.81 m/s²

Calculating time of fall (t)...

\( t = \) \( \frac{ v - u }{ g } \)

\( t = \) \( \frac{20-4}{9.81} \)

\( t = \) 1.631 s

Calculating height (h)...

\( h = \) \( u \cdot \frac{ v - u }{ g } + \frac{1}{2} g \cdot \left( \frac{ v - u }{ g } \right)^2 \)

\( h = \) \(4\times \frac{20-4}{9.81} + \frac{1}{2} \times9.81\times \left( \frac{20-4}{9.81} \right)^2 \)

\( h = \) 19.5719 m

4

Consider that a bird dropped chicken lollipop from top of a building of height 50 m. Since, the bird slipped it, consider that initial velocity is 0 m/s.
Calculate the time taken by the chicken lollipop to reach ground, and also its final velocity with which it makes contact with ground.

Answer

Given:

  • Height, h = 50 m
  • Initial velocity, u = 0 m/s
  • Acceleration due to gravity, g = 9.81 m/s²

Calculating time of fall (t)...

\( t = \) \( \frac{ - u + \sqrt{ u ^2 + 2 g h } }{ g } \)

\( t = \) \( \frac{ -0+ \sqrt{0^2 + 2 \times9.81\times50} }{9.81} \)

\( t = \) 3.1928 s

Calculating final velocity (v)...

\( v = \) \( \sqrt{ u ^2 + 2 g h } \)

\( v = \) \( \sqrt{0^2 + 2 \times9.81\times50} \)

\( v = \) 31.3209 m/s

5

The same bird throwed another chicken lollipop from top of another building. Consider that we somehow calculated the final velocity to be 50 m/s, time to reach the ground to be 5 s.
Calculate the initial velocity of the chicken lollipop with which the bird has thrown it, and also height of the building.

Answer

Given:

  • Final velocity, v = 50 m/s
  • Time of fall, t = 5 s
  • Acceleration due to gravity, g = 9.81 m/s²

Calculating initial velocity (u)...

\( u = \) \( v - g \cdot t \)

\( u = \) \(50-9.81\times5\)

\( u = \) 0.95 m/s

Calculating height (h)...

\( h = \) \(( v - g \cdot t ) \cdot t + \frac{1}{2} g \cdot t ^2 \)

\( h = \) \((50-9.81\times5) \times5+ \frac{1}{2} \times9.81\times5^2 \)

\( h = \) 127.375 m