Use this free online force converter to change dekanewtons into joules per centimeter instantly. Type in the dekanewtons value, and the equivalent joules per centimeter is calculated for you in real time.
to
Enter your inputs, and the result is calculated in real-time.
Dekanewtons
Joules per Centimeter
How to use this Dekanewtons to Joules per Centimeter Converter 🤔
Follow these steps to convert given Dekanewtons value from Dekanewtons units to Joules per Centimeter units.
Enter the input Dekanewtons value in the text field.
The given Dekanewtons is converted to Joules per Centimeter in realtime ⌚ using the formula, and displayed under the Joules per Centimeter label.
You may copy the resulting Joules per Centimeter value using the Copy button.
Formula
To convert given force from Dekanewtons to Joules per Centimeter, use the following formula.
Joules per Centimeter = Dekanewtons * 1000
Calculation
Calculation will be done after you enter a valid input.
Dekanewtons
A dekanewton (daN) represents 10 newtons of force. It is a convenient unit for representing forces in contexts where newtons are too small, but kilonewtons are too large. Dekanewtons are occasionally used in mechanical and engineering applications.
Joules per Centimeter
Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science.
{
"conversion": "dekanewton-joule-per-centimeter",
"x_slug": "dekanewton",
"y_slug": "joule-per-centimeter",
"x": "daN",
"y": "J/cm",
"x_desc": "Dekanewtons",
"y_desc": "Joules per Centimeter",
"category": "Force",
"symbol": "m",
"formula": "x * 1000",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a boat that requires a force of 50 dekanewtons to pull across the water.<br>Convert this force from dekanewtons to Joules per Centimeter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of pulling boat across the water in dekanewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Dekanewtons)</sub></span> = 50</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from dekanewtons to joules per centimeter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>Force<sub>(Dekanewtons)</sub></span> × 1000</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of pulling boat across the water, <strong>Force<sub>(Dekanewtons)</sub> = 50</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>50</span> × 1000</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 50000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>50 daN</strong> is equal to <strong>50000 J/cm</strong>.</p>\n <p>The force of pulling boat across the water is <strong>50000 J/cm</strong>, in joules per centimeter.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a pulley system lifting a weight using 20 dekanewtons of force.<br>Convert this force from dekanewtons to Joules per Centimeter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of lifting a weight by pulley system in dekanewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Dekanewtons)</sub></span> = 20</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from dekanewtons to joules per centimeter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>Force<sub>(Dekanewtons)</sub></span> × 1000</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of lifting a weight by pulley system, <strong>Force<sub>(Dekanewtons)</sub> = 20</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>20</span> × 1000</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 20000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>20 daN</strong> is equal to <strong>20000 J/cm</strong>.</p>\n <p>The force of lifting a weight by pulley system is <strong>20000 J/cm</strong>, in joules per centimeter.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"x_long_desc": "A dekanewton (daN) represents 10 newtons of force. It is a convenient unit for representing forces in contexts where newtons are too small, but kilonewtons are too large. Dekanewtons are occasionally used in mechanical and engineering applications.",
"y_long_desc": "Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science."
}
ConvertOnline