Use this free online force converter to change dekanewtons into joules per meter instantly. Type in the dekanewtons value, and the equivalent joules per meter is calculated for you in real time.
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Enter your inputs, and the result is calculated in real-time.
Dekanewtons
Joules per Meter
How to use this Dekanewtons to Joules per Meter Converter 🤔
Follow these steps to convert given Dekanewtons value from Dekanewtons units to Joules per Meter units.
Enter the input Dekanewtons value in the text field.
The given Dekanewtons is converted to Joules per Meter in realtime ⌚ using the formula, and displayed under the Joules per Meter label.
You may copy the resulting Joules per Meter value using the Copy button.
Formula
To convert given force from Dekanewtons to Joules per Meter, use the following formula.
Joules per Meter = Dekanewtons * 10
Calculation
Calculation will be done after you enter a valid input.
Dekanewtons
A dekanewton (daN) represents 10 newtons of force. It is a convenient unit for representing forces in contexts where newtons are too small, but kilonewtons are too large. Dekanewtons are occasionally used in mechanical and engineering applications.
Joules per Meter
Joule per meter (J/m) is a unit that represents energy per unit length. It is often used in the context of surface tension, where it describes the energy required to increase the surface area of a liquid.
{
"conversion": "dekanewton-joule-per-meter",
"x_slug": "dekanewton",
"y_slug": "joule-per-meter",
"x": "daN",
"y": "J/m",
"x_desc": "Dekanewtons",
"y_desc": "Joules per Meter",
"category": "Force",
"symbol": "m",
"formula": "x * 10",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a boat that requires a force of 50 dekanewtons to pull across the water.<br>Convert this force from dekanewtons to Joules per Meter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of pulling boat across the water in dekanewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Dekanewtons)</sub></span> = 50</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from dekanewtons to joules per meter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Meter)</sub></span> = <span>Force<sub>(Dekanewtons)</sub></span> × 10</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of pulling boat across the water, <strong>Force<sub>(Dekanewtons)</sub> = 50</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = <span>50</span> × 10</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = 500</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>50 daN</strong> is equal to <strong>500 J/m</strong>.</p>\n <p>The force of pulling boat across the water is <strong>500 J/m</strong>, in joules per meter.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a pulley system lifting a weight using 20 dekanewtons of force.<br>Convert this force from dekanewtons to Joules per Meter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of lifting a weight by pulley system in dekanewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Dekanewtons)</sub></span> = 20</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from dekanewtons to joules per meter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Meter)</sub></span> = <span>Force<sub>(Dekanewtons)</sub></span> × 10</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of lifting a weight by pulley system, <strong>Force<sub>(Dekanewtons)</sub> = 20</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = <span>20</span> × 10</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = 200</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>20 daN</strong> is equal to <strong>200 J/m</strong>.</p>\n <p>The force of lifting a weight by pulley system is <strong>200 J/m</strong>, in joules per meter.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"x_long_desc": "A dekanewton (daN) represents 10 newtons of force. It is a convenient unit for representing forces in contexts where newtons are too small, but kilonewtons are too large. Dekanewtons are occasionally used in mechanical and engineering applications.",
"y_long_desc": "Joule per meter (J/m) is a unit that represents energy per unit length. It is often used in the context of surface tension, where it describes the energy required to increase the surface area of a liquid."
}