Convert Dekanewtons to Pound Foot per Square Second
Use this free online force converter to change dekanewtons into pound foot per square second instantly. Type in the dekanewtons value, and the equivalent pound foot per square second is calculated for you in real time.
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Dekanewtons
Pound Foot per Square Second
How to use this Dekanewtons to Pound Foot per Square Second Converter 🤔
Follow these steps to convert given Dekanewtons value from Dekanewtons units to Pound Foot per Square Second units.
Enter the input Dekanewtons value in the text field.
The given Dekanewtons is converted to Pound Foot per Square Second in realtime ⌚ using the formula, and displayed under the Pound Foot per Square Second label.
You may copy the resulting Pound Foot per Square Second value using the Copy button.
Formula
To convert given force from Dekanewtons to Pound Foot per Square Second, use the following formula.
Pound Foot per Square Second = Dekanewtons * 72.330138512099
Calculation
Calculation will be done after you enter a valid input.
Dekanewtons
A dekanewton (daN) represents 10 newtons of force. It is a convenient unit for representing forces in contexts where newtons are too small, but kilonewtons are too large. Dekanewtons are occasionally used in mechanical and engineering applications.
Pound Foot per Square Second
Pound foot per square second is a unit used to describe force in the FPS system. It is sometimes used in older engineering contexts or for specialized calculations.
{
"conversion": "dekanewton-pound-foot-per-square-second",
"x_slug": "dekanewton",
"y_slug": "pound-foot-per-square-second",
"x": "daN",
"y": "lbf·ft/s²",
"x_desc": "Dekanewtons",
"y_desc": "Pound Foot per Square Second",
"category": "Force",
"symbol": "m",
"formula": "x * 72.330138512099",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a boat that requires a force of 50 dekanewtons to pull across the water.<br>Convert this force from dekanewtons to Pound Foot per Square Second.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of pulling boat across the water in dekanewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Dekanewtons)</sub></span> = 50</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from dekanewtons to pound foot per square second is:</p>\n <p class=\"formula step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>Force<sub>(Dekanewtons)</sub></span> × 72.330138512099</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of pulling boat across the water, <strong>Force<sub>(Dekanewtons)</sub> = 50</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>50</span> × 72.330138512099</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = 3616.5069</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>50 daN</strong> is equal to <strong>3616.5069 lbf·ft/s²</strong>.</p>\n <p>The force of pulling boat across the water is <strong>3616.5069 lbf·ft/s²</strong>, in pound foot per square second.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a pulley system lifting a weight using 20 dekanewtons of force.<br>Convert this force from dekanewtons to Pound Foot per Square Second.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of lifting a weight by pulley system in dekanewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Dekanewtons)</sub></span> = 20</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from dekanewtons to pound foot per square second is:</p>\n <p class=\"formula step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>Force<sub>(Dekanewtons)</sub></span> × 72.330138512099</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of lifting a weight by pulley system, <strong>Force<sub>(Dekanewtons)</sub> = 20</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>20</span> × 72.330138512099</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = 1446.6028</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>20 daN</strong> is equal to <strong>1446.6028 lbf·ft/s²</strong>.</p>\n <p>The force of lifting a weight by pulley system is <strong>1446.6028 lbf·ft/s²</strong>, in pound foot per square second.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"x_long_desc": "A dekanewton (daN) represents 10 newtons of force. It is a convenient unit for representing forces in contexts where newtons are too small, but kilonewtons are too large. Dekanewtons are occasionally used in mechanical and engineering applications.",
"y_long_desc": "Pound foot per square second is a unit used to describe force in the FPS system. It is sometimes used in older engineering contexts or for specialized calculations."
}
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