Use this free online force converter to change dekanewtons into short ton-force instantly. Type in the dekanewtons value, and the equivalent short ton-force is calculated for you in real time.
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Dekanewtons
Short Ton-Force
How to use this Dekanewtons to Short Ton-Force Converter 🤔
Follow these steps to convert given Dekanewtons value from Dekanewtons units to Short Ton-Force units.
Enter the input Dekanewtons value in the text field.
The given Dekanewtons is converted to Short Ton-Force in realtime ⌚ using the formula, and displayed under the Short Ton-Force label.
You may copy the resulting Short Ton-Force value using the Copy button.
Formula
To convert given force from Dekanewtons to Short Ton-Force, use the following formula.
Short Ton-Force = Dekanewtons * 0.0011240447154986
Calculation
Calculation will be done after you enter a valid input.
Dekanewtons
A dekanewton (daN) represents 10 newtons of force. It is a convenient unit for representing forces in contexts where newtons are too small, but kilonewtons are too large. Dekanewtons are occasionally used in mechanical and engineering applications.
Short Ton-Force
Short ton-force represents the force exerted by the weight of a short ton (2,000 pounds) under standard gravity. It is used primarily in the United States to describe large forces in engineering, construction, and mechanics.
{
"conversion": "dekanewton-ton-force-short",
"x_slug": "dekanewton",
"y_slug": "ton-force-short",
"x": "daN",
"y": "short tonf",
"x_desc": "Dekanewtons",
"y_desc": "Short Ton-Force",
"category": "Force",
"symbol": "m",
"formula": "x * 0.0011240447154986",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a boat that requires a force of 50 dekanewtons to pull across the water.<br>Convert this force from dekanewtons to Short Ton-Force.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of pulling boat across the water in dekanewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Dekanewtons)</sub></span> = 50</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from dekanewtons to short ton-force is:</p>\n <p class=\"formula step\"><span>Force<sub>(Short Ton-Force)</sub></span> = <span>Force<sub>(Dekanewtons)</sub></span> × 0.0011240447154986</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of pulling boat across the water, <strong>Force<sub>(Dekanewtons)</sub> = 50</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Short Ton-Force)</sub></span> = <span>50</span> × 0.0011240447154986</p>\n <p class=\"step\"><span>Force<sub>(Short Ton-Force)</sub></span> = 0.05620223577</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>50 daN</strong> is equal to <strong>0.05620223577 short tonf</strong>.</p>\n <p>The force of pulling boat across the water is <strong>0.05620223577 short tonf</strong>, in short ton-force.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a pulley system lifting a weight using 20 dekanewtons of force.<br>Convert this force from dekanewtons to Short Ton-Force.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of lifting a weight by pulley system in dekanewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Dekanewtons)</sub></span> = 20</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from dekanewtons to short ton-force is:</p>\n <p class=\"formula step\"><span>Force<sub>(Short Ton-Force)</sub></span> = <span>Force<sub>(Dekanewtons)</sub></span> × 0.0011240447154986</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of lifting a weight by pulley system, <strong>Force<sub>(Dekanewtons)</sub> = 20</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Short Ton-Force)</sub></span> = <span>20</span> × 0.0011240447154986</p>\n <p class=\"step\"><span>Force<sub>(Short Ton-Force)</sub></span> = 0.02248089431</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>20 daN</strong> is equal to <strong>0.02248089431 short tonf</strong>.</p>\n <p>The force of lifting a weight by pulley system is <strong>0.02248089431 short tonf</strong>, in short ton-force.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"x_long_desc": "A dekanewton (daN) represents 10 newtons of force. It is a convenient unit for representing forces in contexts where newtons are too small, but kilonewtons are too large. Dekanewtons are occasionally used in mechanical and engineering applications.",
"y_long_desc": "Short ton-force represents the force exerted by the weight of a short ton (2,000 pounds) under standard gravity. It is used primarily in the United States to describe large forces in engineering, construction, and mechanics."
}
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