Use this free online force converter to change exanewtons into dekanewtons instantly. Type in the exanewtons value, and the equivalent dekanewtons is calculated for you in real time.
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Exanewtons
Dekanewtons
How to use this Exanewtons to Dekanewtons Converter 🤔
Follow these steps to convert given Exanewtons value from Exanewtons units to Dekanewtons units.
Enter the input Exanewtons value in the text field.
The given Exanewtons is converted to Dekanewtons in realtime ⌚ using the formula, and displayed under the Dekanewtons label.
You may copy the resulting Dekanewtons value using the Copy button.
Formula
To convert given force from Exanewtons to Dekanewtons, use the following formula.
Dekanewtons = Exanewtons * 1e+17
Calculation
Calculation will be done after you enter a valid input.
Exanewtons
An exanewton (EN) is an incredibly large unit of force equal to 1018 newtons. It is rarely used in practical scenarios but could hypothetically be used to describe astronomical events or forces on a cosmic scale, such as the gravitational force between celestial bodies.
Dekanewtons
A dekanewton (daN) represents 10 newtons of force. It is a convenient unit for representing forces in contexts where newtons are too small, but kilonewtons are too large. Dekanewtons are occasionally used in mechanical and engineering applications.
{
"conversion": "exanewton-dekanewton",
"x_slug": "exanewton",
"y_slug": "dekanewton",
"x": "EN",
"y": "daN",
"x_desc": "Exanewtons",
"y_desc": "Dekanewtons",
"category": "Force",
"symbol": "m",
"formula": "x * 1e+17",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a theoretical celestial object exerting a force of 1 exanewton on nearby stars.<br>Convert this force from exanewtons to Dekanewtons.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of celestial object in exanewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Exanewtons)</sub></span> = 1</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from exanewtons to dekanewtons is:</p>\n <p class=\"formula step\"><span>Force<sub>(Dekanewtons)</sub></span> = <span>Force<sub>(Exanewtons)</sub></span> × 1e+17</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of celestial object, <strong>Force<sub>(Exanewtons)</sub> = 1</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Dekanewtons)</sub></span> = <span>1</span> × 1e+17</p>\n <p class=\"step\"><span>Force<sub>(Dekanewtons)</sub></span> = 100000000000000000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>1 EN</strong> is equal to <strong>100000000000000000 daN</strong>.</p>\n <p>The force of celestial object is <strong>100000000000000000 daN</strong>, in dekanewtons.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider the gravitational force between two massive objects is 0.5 exanewtons.<br>Convert this force from exanewtons to Dekanewtons.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of gravitation between massive objects in exanewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Exanewtons)</sub></span> = 0.5</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from exanewtons to dekanewtons is:</p>\n <p class=\"formula step\"><span>Force<sub>(Dekanewtons)</sub></span> = <span>Force<sub>(Exanewtons)</sub></span> × 1e+17</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of gravitation between massive objects, <strong>Force<sub>(Exanewtons)</sub> = 0.5</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Dekanewtons)</sub></span> = <span>0.5</span> × 1e+17</p>\n <p class=\"step\"><span>Force<sub>(Dekanewtons)</sub></span> = 50000000000000000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>0.5 EN</strong> is equal to <strong>50000000000000000 daN</strong>.</p>\n <p>The force of gravitation between massive objects is <strong>50000000000000000 daN</strong>, in dekanewtons.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"x_long_desc": "An exanewton (EN) is an incredibly large unit of force equal to 10<sup>18</sup> newtons. It is rarely used in practical scenarios but could hypothetically be used to describe astronomical events or forces on a cosmic scale, such as the gravitational force between celestial bodies.",
"y_long_desc": "A dekanewton (daN) represents 10 newtons of force. It is a convenient unit for representing forces in contexts where newtons are too small, but kilonewtons are too large. Dekanewtons are occasionally used in mechanical and engineering applications."
}