Use this free online force converter to change exanewtons into joules per meter instantly. Type in the exanewtons value, and the equivalent joules per meter is calculated for you in real time.
to
Enter your inputs, and the result is calculated in real-time.
Exanewtons
Joules per Meter
How to use this Exanewtons to Joules per Meter Converter 🤔
Follow these steps to convert given Exanewtons value from Exanewtons units to Joules per Meter units.
Enter the input Exanewtons value in the text field.
The given Exanewtons is converted to Joules per Meter in realtime ⌚ using the formula, and displayed under the Joules per Meter label.
You may copy the resulting Joules per Meter value using the Copy button.
Formula
To convert given force from Exanewtons to Joules per Meter, use the following formula.
Joules per Meter = Exanewtons * 1e+18
Calculation
Calculation will be done after you enter a valid input.
Exanewtons
An exanewton (EN) is an incredibly large unit of force equal to 1018 newtons. It is rarely used in practical scenarios but could hypothetically be used to describe astronomical events or forces on a cosmic scale, such as the gravitational force between celestial bodies.
Joules per Meter
Joule per meter (J/m) is a unit that represents energy per unit length. It is often used in the context of surface tension, where it describes the energy required to increase the surface area of a liquid.
{
"conversion": "exanewton-joule-per-meter",
"x_slug": "exanewton",
"y_slug": "joule-per-meter",
"x": "EN",
"y": "J/m",
"x_desc": "Exanewtons",
"y_desc": "Joules per Meter",
"category": "Force",
"symbol": "m",
"formula": "x * 1e+18",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a theoretical celestial object exerting a force of 1 exanewton on nearby stars.<br>Convert this force from exanewtons to Joules per Meter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of celestial object in exanewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Exanewtons)</sub></span> = 1</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from exanewtons to joules per meter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Meter)</sub></span> = <span>Force<sub>(Exanewtons)</sub></span> × 1e+18</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of celestial object, <strong>Force<sub>(Exanewtons)</sub> = 1</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = <span>1</span> × 1e+18</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = 1000000000000000000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>1 EN</strong> is equal to <strong>1000000000000000000 J/m</strong>.</p>\n <p>The force of celestial object is <strong>1000000000000000000 J/m</strong>, in joules per meter.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider the gravitational force between two massive objects is 0.5 exanewtons.<br>Convert this force from exanewtons to Joules per Meter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of gravitation between massive objects in exanewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Exanewtons)</sub></span> = 0.5</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from exanewtons to joules per meter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Meter)</sub></span> = <span>Force<sub>(Exanewtons)</sub></span> × 1e+18</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of gravitation between massive objects, <strong>Force<sub>(Exanewtons)</sub> = 0.5</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = <span>0.5</span> × 1e+18</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = 500000000000000000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>0.5 EN</strong> is equal to <strong>500000000000000000 J/m</strong>.</p>\n <p>The force of gravitation between massive objects is <strong>500000000000000000 J/m</strong>, in joules per meter.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"x_long_desc": "An exanewton (EN) is an incredibly large unit of force equal to 10<sup>18</sup> newtons. It is rarely used in practical scenarios but could hypothetically be used to describe astronomical events or forces on a cosmic scale, such as the gravitational force between celestial bodies.",
"y_long_desc": "Joule per meter (J/m) is a unit that represents energy per unit length. It is often used in the context of surface tension, where it describes the energy required to increase the surface area of a liquid."
}