Use this free online force converter to change gram-force into joules per meter instantly. Type in the gram-force value, and the equivalent joules per meter is calculated for you in real time.
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Enter your inputs, and the result is calculated in real-time.
Gram-Force
Joules per Meter
How to use this Gram-Force to Joules per Meter Converter 🤔
Follow these steps to convert given Gram-Force value from Gram-Force units to Joules per Meter units.
Enter the input Gram-Force value in the text field.
The given Gram-Force is converted to Joules per Meter in realtime ⌚ using the formula, and displayed under the Joules per Meter label.
You may copy the resulting Joules per Meter value using the Copy button.
Formula
To convert given force from Gram-Force to Joules per Meter, use the following formula.
Joules per Meter = Gram-Force * 0.009806650000000272
Calculation
Calculation will be done after you enter a valid input.
Gram-Force
Gram-force (gf) is the force exerted by the weight of one gram under standard gravity. It’s a small unit of force often used in applications like measuring the tension of lightweight objects or precision instruments. Although it’s not an SI unit, gram-force provides an intuitive way to represent small forces.
Joules per Meter
Joule per meter (J/m) is a unit that represents energy per unit length. It is often used in the context of surface tension, where it describes the energy required to increase the surface area of a liquid.
{
"conversion": "gram-force-joule-per-meter",
"x_slug": "gram-force",
"y_slug": "joule-per-meter",
"x": "gf",
"y": "J/m",
"x_desc": "Gram-Force",
"y_desc": "Joules per Meter",
"category": "Force",
"symbol": "m",
"formula": "x * 0.009806650000000272",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a small object weighing 300 grams, applying a force of 300 gram-force.<br>Convert this force from gram-force to Joules per Meter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of object in gram-force is:</p>\n <p class=\"step\"><span>Force<sub>(Gram-Force)</sub></span> = 300</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from gram-force to joules per meter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Meter)</sub></span> = <span>Force<sub>(Gram-Force)</sub></span> × 0.009806650000000272</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of object, <strong>Force<sub>(Gram-Force)</sub> = 300</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = <span>300</span> × 0.009806650000000272</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = 2.942</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>300 gf</strong> is equal to <strong>2.942 J/m</strong>.</p>\n <p>The force of object is <strong>2.942 J/m</strong>, in joules per meter.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a feather that weighs 50 gram-force.<br>Convert this force from gram-force to Joules per Meter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of feather in gram-force is:</p>\n <p class=\"step\"><span>Force<sub>(Gram-Force)</sub></span> = 50</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from gram-force to joules per meter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Meter)</sub></span> = <span>Force<sub>(Gram-Force)</sub></span> × 0.009806650000000272</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of feather, <strong>Force<sub>(Gram-Force)</sub> = 50</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = <span>50</span> × 0.009806650000000272</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = 0.4903</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>50 gf</strong> is equal to <strong>0.4903 J/m</strong>.</p>\n <p>The force of feather is <strong>0.4903 J/m</strong>, in joules per meter.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"x_long_desc": "Gram-force (gf) is the force exerted by the weight of one gram under standard gravity. It’s a small unit of force often used in applications like measuring the tension of lightweight objects or precision instruments. Although it’s not an SI unit, gram-force provides an intuitive way to represent small forces.",
"y_long_desc": "Joule per meter (J/m) is a unit that represents energy per unit length. It is often used in the context of surface tension, where it describes the energy required to increase the surface area of a liquid."
}
ConvertOnline