Use this free online force converter to change joules per centimeter into attonewtons instantly. Type in the joules per centimeter value, and the equivalent attonewtons is calculated for you in real time.
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Enter your inputs, and the result is calculated in real-time.
Joules per Centimeter
Attonewtons
How to use this Joules per Centimeter to Attonewtons Converter 🤔
Follow these steps to convert given Joules per Centimeter value from Joules per Centimeter units to Attonewtons units.
Enter the input Joules per Centimeter value in the text field.
The given Joules per Centimeter is converted to Attonewtons in realtime ⌚ using the formula, and displayed under the Attonewtons label.
You may copy the resulting Attonewtons value using the Copy button.
Formula
To convert given force from Joules per Centimeter to Attonewtons, use the following formula.
Attonewtons = Joules per Centimeter * 1e+16
Calculation
Calculation will be done after you enter a valid input.
Joules per Centimeter
Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science.
Attonewtons
An attonewton (aN) is 10-18 newtons. It is a unit used in the field of quantum physics and nanotechnology to express forces at an almost unimaginable scale, such as the force exerted by a single photon on a particle.
{
"conversion": "joule-per-centimeter-attonewton",
"x_slug": "joule-per-centimeter",
"y_slug": "attonewton",
"x": "J/cm",
"y": "aN",
"x_desc": "Joules per Centimeter",
"y_desc": "Attonewtons",
"category": "Force",
"symbol": "m",
"formula": "x * 1e+16",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a force applied over 200 centimeters with an energy of 500 joules per centimeter.<br>Convert this force from joule-per-centimeter to Attonewtons.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force in joules per centimeter is:</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 500</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from joules per centimeter to attonewtons is:</p>\n <p class=\"formula step\"><span>Force<sub>(Attonewtons)</sub></span> = <span>Force<sub>(Joules per Centimeter)</sub></span> × 1e+16</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight <strong>Force<sub>(Joules per Centimeter)</sub> = 500</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Attonewtons)</sub></span> = <span>500</span> × 1e+16</p>\n <p class=\"step\"><span>Force<sub>(Attonewtons)</sub></span> = 5000000000000000000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>500 J/cm</strong> is equal to <strong>5000000000000000000 aN</strong>.</p>\n <p>The force is <strong>5000000000000000000 aN</strong>, in attonewtons.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a machine that exerts 1,000 joules per centimeter while compressing material.<br>Convert this force from joule-per-centimeter to Attonewtons.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of machine in joules per centimeter is:</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 1000</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from joules per centimeter to attonewtons is:</p>\n <p class=\"formula step\"><span>Force<sub>(Attonewtons)</sub></span> = <span>Force<sub>(Joules per Centimeter)</sub></span> × 1e+16</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of machine, <strong>Force<sub>(Joules per Centimeter)</sub> = 1000</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Attonewtons)</sub></span> = <span>1000</span> × 1e+16</p>\n <p class=\"step\"><span>Force<sub>(Attonewtons)</sub></span> = 10000000000000000000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>1000 J/cm</strong> is equal to <strong>10000000000000000000 aN</strong>.</p>\n <p>The force of machine is <strong>10000000000000000000 aN</strong>, in attonewtons.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"y_long_desc": "An attonewton (aN) is 10<sup>-18</sup> newtons. It is a unit used in the field of quantum physics and nanotechnology to express forces at an almost unimaginable scale, such as the force exerted by a single photon on a particle.",
"x_long_desc": "Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science."
}