Use this free online force converter to change joules per centimeter into kilogram-force instantly. Type in the joules per centimeter value, and the equivalent kilogram-force is calculated for you in real time.
to
Enter your inputs, and the result is calculated in real-time.
Joules per Centimeter
Kilogram-Force
How to use this Joules per Centimeter to Kilogram-Force Converter 🤔
Follow these steps to convert given Joules per Centimeter value from Joules per Centimeter units to Kilogram-Force units.
Enter the input Joules per Centimeter value in the text field.
The given Joules per Centimeter is converted to Kilogram-Force in realtime ⌚ using the formula, and displayed under the Kilogram-Force label.
You may copy the resulting Kilogram-Force value using the Copy button.
Formula
To convert given force from Joules per Centimeter to Kilogram-Force, use the following formula.
Kilogram-Force = Joules per Centimeter * 0.0010197162129779
Calculation
Calculation will be done after you enter a valid input.
Joules per Centimeter
Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science.
Kilogram-Force
Kilogram-force (kgf) is the force exerted by the weight of one kilogram under standard gravity. It is often used in engineering to describe the force of everyday objects and loads, such as the force exerted by a heavy tool or piece of equipment. It is a non-SI unit but still finds practical use in many fields.
{
"conversion": "joule-per-centimeter-kilogram-force",
"x_slug": "joule-per-centimeter",
"y_slug": "kilogram-force",
"x": "J/cm",
"y": "kgf",
"x_desc": "Joules per Centimeter",
"y_desc": "Kilogram-Force",
"category": "Force",
"symbol": "m",
"formula": "x * 0.0010197162129779",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a force applied over 200 centimeters with an energy of 500 joules per centimeter.<br>Convert this force from joule-per-centimeter to Kilogram-Force.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force in joules per centimeter is:</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 500</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from joules per centimeter to kilogram-force is:</p>\n <p class=\"formula step\"><span>Force<sub>(Kilogram-Force)</sub></span> = <span>Force<sub>(Joules per Centimeter)</sub></span> × 0.0010197162129779</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight <strong>Force<sub>(Joules per Centimeter)</sub> = 500</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Kilogram-Force)</sub></span> = <span>500</span> × 0.0010197162129779</p>\n <p class=\"step\"><span>Force<sub>(Kilogram-Force)</sub></span> = 0.5099</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>500 J/cm</strong> is equal to <strong>0.5099 kgf</strong>.</p>\n <p>The force is <strong>0.5099 kgf</strong>, in kilogram-force.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a machine that exerts 1,000 joules per centimeter while compressing material.<br>Convert this force from joule-per-centimeter to Kilogram-Force.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of machine in joules per centimeter is:</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 1000</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from joules per centimeter to kilogram-force is:</p>\n <p class=\"formula step\"><span>Force<sub>(Kilogram-Force)</sub></span> = <span>Force<sub>(Joules per Centimeter)</sub></span> × 0.0010197162129779</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of machine, <strong>Force<sub>(Joules per Centimeter)</sub> = 1000</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Kilogram-Force)</sub></span> = <span>1000</span> × 0.0010197162129779</p>\n <p class=\"step\"><span>Force<sub>(Kilogram-Force)</sub></span> = 1.0197</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>1000 J/cm</strong> is equal to <strong>1.0197 kgf</strong>.</p>\n <p>The force of machine is <strong>1.0197 kgf</strong>, in kilogram-force.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"y_long_desc": "Kilogram-force (kgf) is the force exerted by the weight of one kilogram under standard gravity. It is often used in engineering to describe the force of everyday objects and loads, such as the force exerted by a heavy tool or piece of equipment. It is a non-SI unit but still finds practical use in many fields.",
"x_long_desc": "Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science."
}