Use this free online force converter to change joules per centimeter into kilonewtons instantly. Type in the joules per centimeter value, and the equivalent kilonewtons is calculated for you in real time.
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Enter your inputs, and the result is calculated in real-time.
Joules per Centimeter
Kilonewtons
How to use this Joules per Centimeter to Kilonewtons Converter 🤔
Follow these steps to convert given Joules per Centimeter value from Joules per Centimeter units to Kilonewtons units.
Enter the input Joules per Centimeter value in the text field.
The given Joules per Centimeter is converted to Kilonewtons in realtime ⌚ using the formula, and displayed under the Kilonewtons label.
You may copy the resulting Kilonewtons value using the Copy button.
Formula
To convert given force from Joules per Centimeter to Kilonewtons, use the following formula.
Kilonewtons = Joules per Centimeter * 1e-5
Calculation
Calculation will be done after you enter a valid input.
Joules per Centimeter
Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science.
Kilonewtons
A kilonewton (kN) is equal to 1,000 newtons. It is often used in engineering to express larger forces, such as the load-bearing capacity of materials or the thrust produced by rockets. Kilonewtons make it easier to work with the typically larger forces involved in construction, aerospace, and structural analysis.
{
"conversion": "joule-per-centimeter-kilonewton",
"x_slug": "joule-per-centimeter",
"y_slug": "kilonewton",
"x": "J/cm",
"y": "kN",
"x_desc": "Joules per Centimeter",
"y_desc": "Kilonewtons",
"category": "Force",
"symbol": "m",
"formula": "x * 1e-5",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a force applied over 200 centimeters with an energy of 500 joules per centimeter.<br>Convert this force from joule-per-centimeter to Kilonewtons.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force in joules per centimeter is:</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 500</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from joules per centimeter to kilonewtons is:</p>\n <p class=\"formula step\"><span>Force<sub>(Kilonewtons)</sub></span> = <span>Force<sub>(Joules per Centimeter)</sub></span> × 1e-5</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight <strong>Force<sub>(Joules per Centimeter)</sub> = 500</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Kilonewtons)</sub></span> = <span>500</span> × 1e-5</p>\n <p class=\"step\"><span>Force<sub>(Kilonewtons)</sub></span> = 0.005</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>500 J/cm</strong> is equal to <strong>0.005 kN</strong>.</p>\n <p>The force is <strong>0.005 kN</strong>, in kilonewtons.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a machine that exerts 1,000 joules per centimeter while compressing material.<br>Convert this force from joule-per-centimeter to Kilonewtons.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of machine in joules per centimeter is:</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 1000</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from joules per centimeter to kilonewtons is:</p>\n <p class=\"formula step\"><span>Force<sub>(Kilonewtons)</sub></span> = <span>Force<sub>(Joules per Centimeter)</sub></span> × 1e-5</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of machine, <strong>Force<sub>(Joules per Centimeter)</sub> = 1000</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Kilonewtons)</sub></span> = <span>1000</span> × 1e-5</p>\n <p class=\"step\"><span>Force<sub>(Kilonewtons)</sub></span> = 0.01</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>1000 J/cm</strong> is equal to <strong>0.01 kN</strong>.</p>\n <p>The force of machine is <strong>0.01 kN</strong>, in kilonewtons.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"y_long_desc": "A kilonewton (kN) is equal to 1,000 newtons. It is often used in engineering to express larger forces, such as the load-bearing capacity of materials or the thrust produced by rockets. Kilonewtons make it easier to work with the typically larger forces involved in construction, aerospace, and structural analysis.",
"x_long_desc": "Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science."
}
ConvertOnline