Use this free online force converter to change joules per centimeter into meganewtons instantly. Type in the joules per centimeter value, and the equivalent meganewtons is calculated for you in real time.
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Enter your inputs, and the result is calculated in real-time.
Joules per Centimeter
Meganewtons
How to use this Joules per Centimeter to Meganewtons Converter 🤔
Follow these steps to convert given Joules per Centimeter value from Joules per Centimeter units to Meganewtons units.
Enter the input Joules per Centimeter value in the text field.
The given Joules per Centimeter is converted to Meganewtons in realtime ⌚ using the formula, and displayed under the Meganewtons label.
You may copy the resulting Meganewtons value using the Copy button.
Formula
To convert given force from Joules per Centimeter to Meganewtons, use the following formula.
Meganewtons = Joules per Centimeter * 1e-8
Calculation
Calculation will be done after you enter a valid input.
Joules per Centimeter
Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science.
Meganewtons
A meganewton (MN) is 106 newtons. It’s commonly used in fields like aerospace engineering to describe the force exerted by rockets or the loads in large structures. Meganeutons are an appropriate unit for expressing massive forces that exceed the capacity of kilonewtons.
{
"conversion": "joule-per-centimeter-meganewton",
"x_slug": "joule-per-centimeter",
"y_slug": "meganewton",
"x": "J/cm",
"y": "MN",
"x_desc": "Joules per Centimeter",
"y_desc": "Meganewtons",
"category": "Force",
"symbol": "m",
"formula": "x * 1e-8",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a force applied over 200 centimeters with an energy of 500 joules per centimeter.<br>Convert this force from joule-per-centimeter to Meganewtons.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force in joules per centimeter is:</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 500</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from joules per centimeter to meganewtons is:</p>\n <p class=\"formula step\"><span>Force<sub>(Meganewtons)</sub></span> = <span>Force<sub>(Joules per Centimeter)</sub></span> × 1e-8</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight <strong>Force<sub>(Joules per Centimeter)</sub> = 500</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Meganewtons)</sub></span> = <span>500</span> × 1e-8</p>\n <p class=\"step\"><span>Force<sub>(Meganewtons)</sub></span> = 0.000005</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>500 J/cm</strong> is equal to <strong>0.000005 MN</strong>.</p>\n <p>The force is <strong>0.000005 MN</strong>, in meganewtons.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a machine that exerts 1,000 joules per centimeter while compressing material.<br>Convert this force from joule-per-centimeter to Meganewtons.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of machine in joules per centimeter is:</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 1000</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from joules per centimeter to meganewtons is:</p>\n <p class=\"formula step\"><span>Force<sub>(Meganewtons)</sub></span> = <span>Force<sub>(Joules per Centimeter)</sub></span> × 1e-8</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of machine, <strong>Force<sub>(Joules per Centimeter)</sub> = 1000</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Meganewtons)</sub></span> = <span>1000</span> × 1e-8</p>\n <p class=\"step\"><span>Force<sub>(Meganewtons)</sub></span> = 0.00001</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>1000 J/cm</strong> is equal to <strong>0.00001 MN</strong>.</p>\n <p>The force of machine is <strong>0.00001 MN</strong>, in meganewtons.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"y_long_desc": "A meganewton (MN) is 10<sup>6</sup> newtons. It’s commonly used in fields like aerospace engineering to describe the force exerted by rockets or the loads in large structures. Meganeutons are an appropriate unit for expressing massive forces that exceed the capacity of kilonewtons.",
"x_long_desc": "Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science."
}