Use this free online force converter to change joules per centimeter into micronewtons instantly. Type in the joules per centimeter value, and the equivalent micronewtons is calculated for you in real time.
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Enter your inputs, and the result is calculated in real-time.
Joules per Centimeter
Micronewtons
How to use this Joules per Centimeter to Micronewtons Converter 🤔
Follow these steps to convert given Joules per Centimeter value from Joules per Centimeter units to Micronewtons units.
Enter the input Joules per Centimeter value in the text field.
The given Joules per Centimeter is converted to Micronewtons in realtime ⌚ using the formula, and displayed under the Micronewtons label.
You may copy the resulting Micronewtons value using the Copy button.
Formula
To convert given force from Joules per Centimeter to Micronewtons, use the following formula.
Micronewtons = Joules per Centimeter * 1e+4
Calculation
Calculation will be done after you enter a valid input.
Joules per Centimeter
Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science.
Micronewtons
A micronewton (µN) is equal to one-millionth of a newton. This unit is useful in contexts like aerospace and nanoengineering, where extremely small forces come into play, such as measuring the thrust of small satellite propulsion systems.
{
"conversion": "joule-per-centimeter-micronewton",
"x_slug": "joule-per-centimeter",
"y_slug": "micronewton",
"x": "J/cm",
"y": "µN",
"x_desc": "Joules per Centimeter",
"y_desc": "Micronewtons",
"category": "Force",
"symbol": "m",
"formula": "x * 1e+4",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a force applied over 200 centimeters with an energy of 500 joules per centimeter.<br>Convert this force from joule-per-centimeter to Micronewtons.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force in joules per centimeter is:</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 500</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from joules per centimeter to micronewtons is:</p>\n <p class=\"formula step\"><span>Force<sub>(Micronewtons)</sub></span> = <span>Force<sub>(Joules per Centimeter)</sub></span> × 1e+4</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight <strong>Force<sub>(Joules per Centimeter)</sub> = 500</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Micronewtons)</sub></span> = <span>500</span> × 1e+4</p>\n <p class=\"step\"><span>Force<sub>(Micronewtons)</sub></span> = 5000000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>500 J/cm</strong> is equal to <strong>5000000 µN</strong>.</p>\n <p>The force is <strong>5000000 µN</strong>, in micronewtons.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a machine that exerts 1,000 joules per centimeter while compressing material.<br>Convert this force from joule-per-centimeter to Micronewtons.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of machine in joules per centimeter is:</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 1000</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from joules per centimeter to micronewtons is:</p>\n <p class=\"formula step\"><span>Force<sub>(Micronewtons)</sub></span> = <span>Force<sub>(Joules per Centimeter)</sub></span> × 1e+4</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of machine, <strong>Force<sub>(Joules per Centimeter)</sub> = 1000</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Micronewtons)</sub></span> = <span>1000</span> × 1e+4</p>\n <p class=\"step\"><span>Force<sub>(Micronewtons)</sub></span> = 10000000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>1000 J/cm</strong> is equal to <strong>10000000 µN</strong>.</p>\n <p>The force of machine is <strong>10000000 µN</strong>, in micronewtons.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"y_long_desc": "A micronewton (µN) is equal to one-millionth of a newton. This unit is useful in contexts like aerospace and nanoengineering, where extremely small forces come into play, such as measuring the thrust of small satellite propulsion systems.",
"x_long_desc": "Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science."
}