Use this free online force converter to change joules per centimeter into piconewtons instantly. Type in the joules per centimeter value, and the equivalent piconewtons is calculated for you in real time.
to
Enter your inputs, and the result is calculated in real-time.
Joules per Centimeter
Piconewtons
How to use this Joules per Centimeter to Piconewtons Converter 🤔
Follow these steps to convert given Joules per Centimeter value from Joules per Centimeter units to Piconewtons units.
Enter the input Joules per Centimeter value in the text field.
The given Joules per Centimeter is converted to Piconewtons in realtime ⌚ using the formula, and displayed under the Piconewtons label.
You may copy the resulting Piconewtons value using the Copy button.
Formula
To convert given force from Joules per Centimeter to Piconewtons, use the following formula.
Piconewtons = Joules per Centimeter * 1e+10
Calculation
Calculation will be done after you enter a valid input.
Joules per Centimeter
Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science.
Piconewtons
A piconewton (pN) is one-trillionth of a newton. It’s often used in biophysics to measure forces within cells or the binding strength between molecules, providing a unit that’s suitable for describing the tiny interactions within biological systems.
{
"conversion": "joule-per-centimeter-piconewton",
"x_slug": "joule-per-centimeter",
"y_slug": "piconewton",
"x": "J/cm",
"y": "pN",
"x_desc": "Joules per Centimeter",
"y_desc": "Piconewtons",
"category": "Force",
"symbol": "m",
"formula": "x * 1e+10",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a force applied over 200 centimeters with an energy of 500 joules per centimeter.<br>Convert this force from joule-per-centimeter to Piconewtons.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force in joules per centimeter is:</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 500</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from joules per centimeter to piconewtons is:</p>\n <p class=\"formula step\"><span>Force<sub>(Piconewtons)</sub></span> = <span>Force<sub>(Joules per Centimeter)</sub></span> × 1e+10</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight <strong>Force<sub>(Joules per Centimeter)</sub> = 500</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Piconewtons)</sub></span> = <span>500</span> × 1e+10</p>\n <p class=\"step\"><span>Force<sub>(Piconewtons)</sub></span> = 5000000000000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>500 J/cm</strong> is equal to <strong>5000000000000 pN</strong>.</p>\n <p>The force is <strong>5000000000000 pN</strong>, in piconewtons.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a machine that exerts 1,000 joules per centimeter while compressing material.<br>Convert this force from joule-per-centimeter to Piconewtons.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of machine in joules per centimeter is:</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 1000</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from joules per centimeter to piconewtons is:</p>\n <p class=\"formula step\"><span>Force<sub>(Piconewtons)</sub></span> = <span>Force<sub>(Joules per Centimeter)</sub></span> × 1e+10</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of machine, <strong>Force<sub>(Joules per Centimeter)</sub> = 1000</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Piconewtons)</sub></span> = <span>1000</span> × 1e+10</p>\n <p class=\"step\"><span>Force<sub>(Piconewtons)</sub></span> = 10000000000000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>1000 J/cm</strong> is equal to <strong>10000000000000 pN</strong>.</p>\n <p>The force of machine is <strong>10000000000000 pN</strong>, in piconewtons.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"y_long_desc": "A piconewton (pN) is one-trillionth of a newton. It’s often used in biophysics to measure forces within cells or the binding strength between molecules, providing a unit that’s suitable for describing the tiny interactions within biological systems.",
"x_long_desc": "Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science."
}
ConvertOnline