Use this free online force converter to change joules per meter into piconewtons instantly. Type in the joules per meter value, and the equivalent piconewtons is calculated for you in real time.
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Enter your inputs, and the result is calculated in real-time.
Joules per Meter
Piconewtons
How to use this Joules per Meter to Piconewtons Converter 🤔
Follow these steps to convert given Joules per Meter value from Joules per Meter units to Piconewtons units.
Enter the input Joules per Meter value in the text field.
The given Joules per Meter is converted to Piconewtons in realtime ⌚ using the formula, and displayed under the Piconewtons label.
You may copy the resulting Piconewtons value using the Copy button.
Formula
To convert given force from Joules per Meter to Piconewtons, use the following formula.
Piconewtons = Joules per Meter * 1e+12
Calculation
Calculation will be done after you enter a valid input.
Joules per Meter
Joule per meter (J/m) is a unit that represents energy per unit length. It is often used in the context of surface tension, where it describes the energy required to increase the surface area of a liquid.
Piconewtons
A piconewton (pN) is one-trillionth of a newton. It’s often used in biophysics to measure forces within cells or the binding strength between molecules, providing a unit that’s suitable for describing the tiny interactions within biological systems.
{
"conversion": "joule-per-meter-piconewton",
"x_slug": "joule-per-meter",
"y_slug": "piconewton",
"x": "J/m",
"y": "pN",
"x_desc": "Joules per Meter",
"y_desc": "Piconewtons",
"category": "Force",
"symbol": "m",
"formula": "x * 1e+12",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a force applied over a distance of 500 meters using an energy of 1,000 joules per meter.<br>Convert this force from joule-per-meter to Piconewtons.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of force over distance in joules per meter is:</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = 1000</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from joules per meter to piconewtons is:</p>\n <p class=\"formula step\"><span>Force<sub>(Piconewtons)</sub></span> = <span>Force<sub>(Joules per Meter)</sub></span> × 1e+12</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of force over distance, <strong>Force<sub>(Joules per Meter)</sub> = 1000</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Piconewtons)</sub></span> = <span>1000</span> × 1e+12</p>\n <p class=\"step\"><span>Force<sub>(Piconewtons)</sub></span> = 1000000000000000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>1000 J/m</strong> is equal to <strong>1000000000000000 pN</strong>.</p>\n <p>The force of force over distance is <strong>1000000000000000 pN</strong>, in piconewtons.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider an engine producing 2,000 joules per meter to move a vehicle.<br>Convert this force from joule-per-meter to Piconewtons.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of engine to move vehicle in joules per meter is:</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = 2000</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from joules per meter to piconewtons is:</p>\n <p class=\"formula step\"><span>Force<sub>(Piconewtons)</sub></span> = <span>Force<sub>(Joules per Meter)</sub></span> × 1e+12</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of engine to move vehicle, <strong>Force<sub>(Joules per Meter)</sub> = 2000</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Piconewtons)</sub></span> = <span>2000</span> × 1e+12</p>\n <p class=\"step\"><span>Force<sub>(Piconewtons)</sub></span> = 2000000000000000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>2000 J/m</strong> is equal to <strong>2000000000000000 pN</strong>.</p>\n <p>The force of engine to move vehicle is <strong>2000000000000000 pN</strong>, in piconewtons.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"y_long_desc": "A piconewton (pN) is one-trillionth of a newton. It’s often used in biophysics to measure forces within cells or the binding strength between molecules, providing a unit that’s suitable for describing the tiny interactions within biological systems.",
"x_long_desc": "Joule per meter (J/m) is a unit that represents energy per unit length. It is often used in the context of surface tension, where it describes the energy required to increase the surface area of a liquid."
}