Convert Joules per Meter to Pound Foot per Square Second
Use this free online force converter to change joules per meter into pound foot per square second instantly. Type in the joules per meter value, and the equivalent pound foot per square second is calculated for you in real time.
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Enter your inputs, and the result is calculated in real-time.
Joules per Meter
Pound Foot per Square Second
How to use this Joules per Meter to Pound Foot per Square Second Converter 🤔
Follow these steps to convert given Joules per Meter value from Joules per Meter units to Pound Foot per Square Second units.
Enter the input Joules per Meter value in the text field.
The given Joules per Meter is converted to Pound Foot per Square Second in realtime ⌚ using the formula, and displayed under the Pound Foot per Square Second label.
You may copy the resulting Pound Foot per Square Second value using the Copy button.
Formula
To convert given force from Joules per Meter to Pound Foot per Square Second, use the following formula.
Pound Foot per Square Second = Joules per Meter * 7.2330138512099
Calculation
Calculation will be done after you enter a valid input.
Joules per Meter
Joule per meter (J/m) is a unit that represents energy per unit length. It is often used in the context of surface tension, where it describes the energy required to increase the surface area of a liquid.
Pound Foot per Square Second
Pound foot per square second is a unit used to describe force in the FPS system. It is sometimes used in older engineering contexts or for specialized calculations.
{
"conversion": "joule-per-meter-pound-foot-per-square-second",
"x_slug": "joule-per-meter",
"y_slug": "pound-foot-per-square-second",
"x": "J/m",
"y": "lbf·ft/s²",
"x_desc": "Joules per Meter",
"y_desc": "Pound Foot per Square Second",
"category": "Force",
"symbol": "m",
"formula": "x * 7.2330138512099",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a force applied over a distance of 500 meters using an energy of 1,000 joules per meter.<br>Convert this force from joule-per-meter to Pound Foot per Square Second.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of force over distance in joules per meter is:</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = 1000</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from joules per meter to pound foot per square second is:</p>\n <p class=\"formula step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>Force<sub>(Joules per Meter)</sub></span> × 7.2330138512099</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of force over distance, <strong>Force<sub>(Joules per Meter)</sub> = 1000</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>1000</span> × 7.2330138512099</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = 7233.0139</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>1000 J/m</strong> is equal to <strong>7233.0139 lbf·ft/s²</strong>.</p>\n <p>The force of force over distance is <strong>7233.0139 lbf·ft/s²</strong>, in pound foot per square second.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider an engine producing 2,000 joules per meter to move a vehicle.<br>Convert this force from joule-per-meter to Pound Foot per Square Second.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of engine to move vehicle in joules per meter is:</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = 2000</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from joules per meter to pound foot per square second is:</p>\n <p class=\"formula step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>Force<sub>(Joules per Meter)</sub></span> × 7.2330138512099</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of engine to move vehicle, <strong>Force<sub>(Joules per Meter)</sub> = 2000</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>2000</span> × 7.2330138512099</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = 14466.0277</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>2000 J/m</strong> is equal to <strong>14466.0277 lbf·ft/s²</strong>.</p>\n <p>The force of engine to move vehicle is <strong>14466.0277 lbf·ft/s²</strong>, in pound foot per square second.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
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[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
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[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
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],
[
"teranewton",
"Teranewtons",
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],
[
"giganewton",
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],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
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],
[
"dekanewton",
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[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
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[
"attonewton",
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[
"dyne",
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[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
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[
"kip-force",
"Kip-Force",
"kipf"
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[
"kilopound-force",
"Kilopound-Force",
"kipf"
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[
"pound-force",
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"lbf"
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[
"ounce-force",
"Ounce-Force",
"ozf"
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[
"poundal",
"Poundals",
"pdl"
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[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"x_long_desc": "Joule per meter (J/m) is a unit that represents energy per unit length. It is often used in the context of surface tension, where it describes the energy required to increase the surface area of a liquid.",
"y_long_desc": "Pound foot per square second is a unit used to describe force in the FPS system. It is sometimes used in older engineering contexts or for specialized calculations."
}
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