Use this free online force converter to change kilogram-force into joules per centimeter instantly. Type in the kilogram-force value, and the equivalent joules per centimeter is calculated for you in real time.
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Kilogram-Force
Joules per Centimeter
How to use this Kilogram-Force to Joules per Centimeter Converter 🤔
Follow these steps to convert given Kilogram-Force value from Kilogram-Force units to Joules per Centimeter units.
Enter the input Kilogram-Force value in the text field.
The given Kilogram-Force is converted to Joules per Centimeter in realtime ⌚ using the formula, and displayed under the Joules per Centimeter label.
You may copy the resulting Joules per Centimeter value using the Copy button.
Formula
To convert given force from Kilogram-Force to Joules per Centimeter, use the following formula.
Joules per Centimeter = Kilogram-Force * 980.6650000000271
Calculation
Calculation will be done after you enter a valid input.
Kilogram-Force
Kilogram-force (kgf) is the force exerted by the weight of one kilogram under standard gravity. It is often used in engineering to describe the force of everyday objects and loads, such as the force exerted by a heavy tool or piece of equipment. It is a non-SI unit but still finds practical use in many fields.
Joules per Centimeter
Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science.
{
"conversion": "kilogram-force-joule-per-centimeter",
"x_slug": "kilogram-force",
"y_slug": "joule-per-centimeter",
"x": "kgf",
"y": "J/cm",
"x_desc": "Kilogram-Force",
"y_desc": "Joules per Centimeter",
"category": "Force",
"symbol": "m",
"formula": "x * 980.6650000000271",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a person applying 70 kilogram-force to lift a weight in the gym.<br>Convert this force from kilogram-force to Joules per Centimeter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of lifting the weight in kilogram-force is:</p>\n <p class=\"step\"><span>Force<sub>(Kilogram-Force)</sub></span> = 70</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from kilogram-force to joules per centimeter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>Force<sub>(Kilogram-Force)</sub></span> × 980.6650000000271</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of lifting the weight, <strong>Force<sub>(Kilogram-Force)</sub> = 70</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>70</span> × 980.6650000000271</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 68646.55</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>70 kgf</strong> is equal to <strong>68646.55 J/cm</strong>.</p>\n <p>The force of lifting the weight is <strong>68646.55 J/cm</strong>, in joules per centimeter.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a shopping bag that exerts 5 kilogram-force.<br>Convert this force from kilogram-force to Joules per Centimeter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of shopping bag in kilogram-force is:</p>\n <p class=\"step\"><span>Force<sub>(Kilogram-Force)</sub></span> = 5</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from kilogram-force to joules per centimeter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>Force<sub>(Kilogram-Force)</sub></span> × 980.6650000000271</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of shopping bag, <strong>Force<sub>(Kilogram-Force)</sub> = 5</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>5</span> × 980.6650000000271</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 4903.325</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>5 kgf</strong> is equal to <strong>4903.325 J/cm</strong>.</p>\n <p>The force of shopping bag is <strong>4903.325 J/cm</strong>, in joules per centimeter.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"x_long_desc": "Kilogram-force (kgf) is the force exerted by the weight of one kilogram under standard gravity. It is often used in engineering to describe the force of everyday objects and loads, such as the force exerted by a heavy tool or piece of equipment. It is a non-SI unit but still finds practical use in many fields.",
"y_long_desc": "Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science."
}
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