Convert Kilogram-Force to Pound Foot per Square Second
Use this free online force converter to change kilogram-force into pound foot per square second instantly. Type in the kilogram-force value, and the equivalent pound foot per square second is calculated for you in real time.
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Kilogram-Force
Pound Foot per Square Second
How to use this Kilogram-Force to Pound Foot per Square Second Converter 🤔
Follow these steps to convert given Kilogram-Force value from Kilogram-Force units to Pound Foot per Square Second units.
Enter the input Kilogram-Force value in the text field.
The given Kilogram-Force is converted to Pound Foot per Square Second in realtime ⌚ using the formula, and displayed under the Pound Foot per Square Second label.
You may copy the resulting Pound Foot per Square Second value using the Copy button.
Formula
To convert given force from Kilogram-Force to Pound Foot per Square Second, use the following formula.
Pound Foot per Square Second = Kilogram-Force * 70.93163528396953
Calculation
Calculation will be done after you enter a valid input.
Kilogram-Force
Kilogram-force (kgf) is the force exerted by the weight of one kilogram under standard gravity. It is often used in engineering to describe the force of everyday objects and loads, such as the force exerted by a heavy tool or piece of equipment. It is a non-SI unit but still finds practical use in many fields.
Pound Foot per Square Second
Pound foot per square second is a unit used to describe force in the FPS system. It is sometimes used in older engineering contexts or for specialized calculations.
{
"conversion": "kilogram-force-pound-foot-per-square-second",
"x_slug": "kilogram-force",
"y_slug": "pound-foot-per-square-second",
"x": "kgf",
"y": "lbf·ft/s²",
"x_desc": "Kilogram-Force",
"y_desc": "Pound Foot per Square Second",
"category": "Force",
"symbol": "m",
"formula": "x * 70.93163528396953",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a person applying 70 kilogram-force to lift a weight in the gym.<br>Convert this force from kilogram-force to Pound Foot per Square Second.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of lifting the weight in kilogram-force is:</p>\n <p class=\"step\"><span>Force<sub>(Kilogram-Force)</sub></span> = 70</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from kilogram-force to pound foot per square second is:</p>\n <p class=\"formula step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>Force<sub>(Kilogram-Force)</sub></span> × 70.93163528396953</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of lifting the weight, <strong>Force<sub>(Kilogram-Force)</sub> = 70</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>70</span> × 70.93163528396953</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = 4965.2145</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>70 kgf</strong> is equal to <strong>4965.2145 lbf·ft/s²</strong>.</p>\n <p>The force of lifting the weight is <strong>4965.2145 lbf·ft/s²</strong>, in pound foot per square second.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a shopping bag that exerts 5 kilogram-force.<br>Convert this force from kilogram-force to Pound Foot per Square Second.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of shopping bag in kilogram-force is:</p>\n <p class=\"step\"><span>Force<sub>(Kilogram-Force)</sub></span> = 5</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from kilogram-force to pound foot per square second is:</p>\n <p class=\"formula step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>Force<sub>(Kilogram-Force)</sub></span> × 70.93163528396953</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of shopping bag, <strong>Force<sub>(Kilogram-Force)</sub> = 5</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>5</span> × 70.93163528396953</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = 354.6582</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>5 kgf</strong> is equal to <strong>354.6582 lbf·ft/s²</strong>.</p>\n <p>The force of shopping bag is <strong>354.6582 lbf·ft/s²</strong>, in pound foot per square second.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"x_long_desc": "Kilogram-force (kgf) is the force exerted by the weight of one kilogram under standard gravity. It is often used in engineering to describe the force of everyday objects and loads, such as the force exerted by a heavy tool or piece of equipment. It is a non-SI unit but still finds practical use in many fields.",
"y_long_desc": "Pound foot per square second is a unit used to describe force in the FPS system. It is sometimes used in older engineering contexts or for specialized calculations."
}
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