Use this free online force converter to change kilonewtons into joules per centimeter instantly. Type in the kilonewtons value, and the equivalent joules per centimeter is calculated for you in real time.
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Kilonewtons
Joules per Centimeter
How to use this Kilonewtons to Joules per Centimeter Converter 🤔
Follow these steps to convert given Kilonewtons value from Kilonewtons units to Joules per Centimeter units.
Enter the input Kilonewtons value in the text field.
The given Kilonewtons is converted to Joules per Centimeter in realtime ⌚ using the formula, and displayed under the Joules per Centimeter label.
You may copy the resulting Joules per Centimeter value using the Copy button.
Formula
To convert given force from Kilonewtons to Joules per Centimeter, use the following formula.
Joules per Centimeter = Kilonewtons * 1e+5
Calculation
Calculation will be done after you enter a valid input.
Kilonewtons
A kilonewton (kN) is equal to 1,000 newtons. It is often used in engineering to express larger forces, such as the load-bearing capacity of materials or the thrust produced by rockets. Kilonewtons make it easier to work with the typically larger forces involved in construction, aerospace, and structural analysis.
Joules per Centimeter
Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science.
{
"conversion": "kilonewton-joule-per-centimeter",
"x_slug": "kilonewton",
"y_slug": "joule-per-centimeter",
"x": "kN",
"y": "J/cm",
"x_desc": "Kilonewtons",
"y_desc": "Joules per Centimeter",
"category": "Force",
"symbol": "m",
"formula": "x * 1e+5",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a crane exerting a force of 2 kilonewtons to lift a heavy load.<br>Convert this force from kilonewtons to Joules per Centimeter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of crane lifting a load in kilonewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Kilonewtons)</sub></span> = 2</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from kilonewtons to joules per centimeter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>Force<sub>(Kilonewtons)</sub></span> × 1e+5</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of crane lifting a load, <strong>Force<sub>(Kilonewtons)</sub> = 2</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>2</span> × 1e+5</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 200000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>2 kN</strong> is equal to <strong>200000 J/cm</strong>.</p>\n <p>The force of crane lifting a load is <strong>200000 J/cm</strong>, in joules per centimeter.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider an elevator that requires a force of 5 kilonewtons to lift its weight.<br>Convert this force from kilonewtons to Joules per Centimeter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of elevator in kilonewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Kilonewtons)</sub></span> = 5</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from kilonewtons to joules per centimeter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>Force<sub>(Kilonewtons)</sub></span> × 1e+5</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of elevator, <strong>Force<sub>(Kilonewtons)</sub> = 5</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>5</span> × 1e+5</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 500000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>5 kN</strong> is equal to <strong>500000 J/cm</strong>.</p>\n <p>The force of elevator is <strong>500000 J/cm</strong>, in joules per centimeter.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"x_long_desc": "A kilonewton (kN) is equal to 1,000 newtons. It is often used in engineering to express larger forces, such as the load-bearing capacity of materials or the thrust produced by rockets. Kilonewtons make it easier to work with the typically larger forces involved in construction, aerospace, and structural analysis.",
"y_long_desc": "Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science."
}
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