Use this free online force converter to change kip-force into pound foot per square second instantly. Type in the kip-force value, and the equivalent pound foot per square second is calculated for you in real time.
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Kip-Force
Pound Foot per Square Second
How to use this Kip-Force to Pound Foot per Square Second Converter 🤔
Follow these steps to convert given Kip-Force value from Kip-Force units to Pound Foot per Square Second units.
Enter the input Kip-Force value in the text field.
The given Kip-Force is converted to Pound Foot per Square Second in realtime ⌚ using the formula, and displayed under the Pound Foot per Square Second label.
You may copy the resulting Pound Foot per Square Second value using the Copy button.
Formula
To convert given force from Kip-Force to Pound Foot per Square Second, use the following formula.
Pound Foot per Square Second = Kip-Force * 3.2174048556389036e+4
Calculation
Calculation will be done after you enter a valid input.
Kip-Force
A kip-force (kipf) is equal to 1,000 pounds-force. It is commonly used in structural engineering in the United States to describe the load-carrying capacity of structures and components.
Pound Foot per Square Second
Pound foot per square second is a unit used to describe force in the FPS system. It is sometimes used in older engineering contexts or for specialized calculations.
{
"conversion": "kip-force-pound-foot-per-square-second",
"x_slug": "kip-force",
"y_slug": "pound-foot-per-square-second",
"x": "kipf",
"y": "lbf·ft/s²",
"x_desc": "Kip-Force",
"y_desc": "Pound Foot per Square Second",
"category": "Force",
"symbol": "m",
"formula": "x * 3.2174048556389036e+4",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a construction beam withstanding a force of 4 kip-force.<br>Convert this force from kip-force to Pound Foot per Square Second.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of construction beam in kip-force is:</p>\n <p class=\"step\"><span>Force<sub>(Kip-Force)</sub></span> = 4</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from kip-force to pound foot per square second is:</p>\n <p class=\"formula step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>Force<sub>(Kip-Force)</sub></span> × 3.2174048556389036e+4</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of construction beam, <strong>Force<sub>(Kip-Force)</sub> = 4</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>4</span> × 3.2174048556389036e+4</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = 128696.1942</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>4 kipf</strong> is equal to <strong>128696.1942 lbf·ft/s²</strong>.</p>\n <p>The force of construction beam is <strong>128696.1942 lbf·ft/s²</strong>, in pound foot per square second.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a bridge that can bear 10 kip-force at its central span.<br>Convert this force from kip-force to Pound Foot per Square Second.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of bridge in kip-force is:</p>\n <p class=\"step\"><span>Force<sub>(Kip-Force)</sub></span> = 10</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from kip-force to pound foot per square second is:</p>\n <p class=\"formula step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>Force<sub>(Kip-Force)</sub></span> × 3.2174048556389036e+4</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of bridge, <strong>Force<sub>(Kip-Force)</sub> = 10</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = <span>10</span> × 3.2174048556389036e+4</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = 321740.4856</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>10 kipf</strong> is equal to <strong>321740.4856 lbf·ft/s²</strong>.</p>\n <p>The force of bridge is <strong>321740.4856 lbf·ft/s²</strong>, in pound foot per square second.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"x_long_desc": "A kip-force (kipf) is equal to 1,000 pounds-force. It is commonly used in structural engineering in the United States to describe the load-carrying capacity of structures and components.",
"y_long_desc": "Pound foot per square second is a unit used to describe force in the FPS system. It is sometimes used in older engineering contexts or for specialized calculations."
}
ConvertOnline