Use this free online force converter to change meganewtons into joules per centimeter instantly. Type in the meganewtons value, and the equivalent joules per centimeter is calculated for you in real time.
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Enter your inputs, and the result is calculated in real-time.
Meganewtons
Joules per Centimeter
How to use this Meganewtons to Joules per Centimeter Converter 🤔
Follow these steps to convert given Meganewtons value from Meganewtons units to Joules per Centimeter units.
Enter the input Meganewtons value in the text field.
The given Meganewtons is converted to Joules per Centimeter in realtime ⌚ using the formula, and displayed under the Joules per Centimeter label.
You may copy the resulting Joules per Centimeter value using the Copy button.
Formula
To convert given force from Meganewtons to Joules per Centimeter, use the following formula.
Joules per Centimeter = Meganewtons * 1e+8
Calculation
Calculation will be done after you enter a valid input.
Meganewtons
A meganewton (MN) is 106 newtons. It’s commonly used in fields like aerospace engineering to describe the force exerted by rockets or the loads in large structures. Meganeutons are an appropriate unit for expressing massive forces that exceed the capacity of kilonewtons.
Joules per Centimeter
Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science.
{
"conversion": "meganewton-joule-per-centimeter",
"x_slug": "meganewton",
"y_slug": "joule-per-centimeter",
"x": "MN",
"y": "J/cm",
"x_desc": "Meganewtons",
"y_desc": "Joules per Centimeter",
"category": "Force",
"symbol": "m",
"formula": "x * 1e+8",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a bridge designed to withstand a force of 20 meganewtons.<br>Convert this force from meganewtons to Joules per Centimeter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force in meganewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Meganewtons)</sub></span> = 20</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from meganewtons to joules per centimeter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>Force<sub>(Meganewtons)</sub></span> × 1e+8</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight <strong>Force<sub>(Meganewtons)</sub> = 20</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>20</span> × 1e+8</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 2000000000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>20 MN</strong> is equal to <strong>2000000000 J/cm</strong>.</p>\n <p>The force is <strong>2000000000 J/cm</strong>, in joules per centimeter.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a strong earthquake generating a force of 15 meganewtons on buildings.<br>Convert this force from meganewtons to Joules per Centimeter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of earthquake generating on buildings in meganewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Meganewtons)</sub></span> = 15</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from meganewtons to joules per centimeter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>Force<sub>(Meganewtons)</sub></span> × 1e+8</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of earthquake generating on buildings, <strong>Force<sub>(Meganewtons)</sub> = 15</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>15</span> × 1e+8</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 1500000000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>15 MN</strong> is equal to <strong>1500000000 J/cm</strong>.</p>\n <p>The force of earthquake generating on buildings is <strong>1500000000 J/cm</strong>, in joules per centimeter.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"x_long_desc": "A meganewton (MN) is 10<sup>6</sup> newtons. It’s commonly used in fields like aerospace engineering to describe the force exerted by rockets or the loads in large structures. Meganeutons are an appropriate unit for expressing massive forces that exceed the capacity of kilonewtons.",
"y_long_desc": "Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science."
}