Use this free online force converter to change micronewtons into joules per centimeter instantly. Type in the micronewtons value, and the equivalent joules per centimeter is calculated for you in real time.
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Enter your inputs, and the result is calculated in real-time.
Micronewtons
Joules per Centimeter
How to use this Micronewtons to Joules per Centimeter Converter 🤔
Follow these steps to convert given Micronewtons value from Micronewtons units to Joules per Centimeter units.
Enter the input Micronewtons value in the text field.
The given Micronewtons is converted to Joules per Centimeter in realtime ⌚ using the formula, and displayed under the Joules per Centimeter label.
You may copy the resulting Joules per Centimeter value using the Copy button.
Formula
To convert given force from Micronewtons to Joules per Centimeter, use the following formula.
Joules per Centimeter = Micronewtons * 1e-4
Calculation
Calculation will be done after you enter a valid input.
Micronewtons
A micronewton (µN) is equal to one-millionth of a newton. This unit is useful in contexts like aerospace and nanoengineering, where extremely small forces come into play, such as measuring the thrust of small satellite propulsion systems.
Joules per Centimeter
Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science.
{
"conversion": "micronewton-joule-per-centimeter",
"x_slug": "micronewton",
"y_slug": "joule-per-centimeter",
"x": "µN",
"y": "J/cm",
"x_desc": "Micronewtons",
"y_desc": "Joules per Centimeter",
"category": "Force",
"symbol": "m",
"formula": "x * 1e-4",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a spacecraft experiencing a tiny thrust of 1,000 micronewtons in space.<br>Convert this thrust from micronewtons to Joules per Centimeter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of spacecraft in micronewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Micronewtons)</sub></span> = 1000</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from micronewtons to joules per centimeter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>Force<sub>(Micronewtons)</sub></span> × 1e-4</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of spacecraft, <strong>Force<sub>(Micronewtons)</sub> = 1000</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>1000</span> × 1e-4</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 0.1</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>1000 µN</strong> is equal to <strong>0.1 J/cm</strong>.</p>\n <p>The force of spacecraft is <strong>0.1 J/cm</strong>, in joules per centimeter.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a micro robot that applies 500 micronewtons of force.<br>Convert this force from micronewtons to Joules per Centimeter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of micro robot in micronewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Micronewtons)</sub></span> = 500</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from micronewtons to joules per centimeter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>Force<sub>(Micronewtons)</sub></span> × 1e-4</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of micro robot, <strong>Force<sub>(Micronewtons)</sub> = 500</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>500</span> × 1e-4</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 0.05</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>500 µN</strong> is equal to <strong>0.05 J/cm</strong>.</p>\n <p>The force of micro robot is <strong>0.05 J/cm</strong>, in joules per centimeter.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"x_long_desc": "A micronewton (µN) is equal to one-millionth of a newton. This unit is useful in contexts like aerospace and nanoengineering, where extremely small forces come into play, such as measuring the thrust of small satellite propulsion systems.",
"y_long_desc": "Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science."
}
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