Use this free online force converter to change petanewtons into hectonewtons instantly. Type in the petanewtons value, and the equivalent hectonewtons is calculated for you in real time.
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Enter your inputs, and the result is calculated in real-time.
Petanewtons
Hectonewtons
How to use this Petanewtons to Hectonewtons Converter 🤔
Follow these steps to convert given Petanewtons value from Petanewtons units to Hectonewtons units.
Enter the input Petanewtons value in the text field.
The given Petanewtons is converted to Hectonewtons in realtime ⌚ using the formula, and displayed under the Hectonewtons label.
You may copy the resulting Hectonewtons value using the Copy button.
Formula
To convert given force from Petanewtons to Hectonewtons, use the following formula.
Hectonewtons = Petanewtons * 1e+13
Calculation
Calculation will be done after you enter a valid input.
Petanewtons
A petanewton (PT) is equal to 1015 newtons. It’s an extremely large unit of force, mostly theoretical, used in astrophysics or high-energy physics to describe forces acting at a massive scale, such as between planets or in star formation.
Hectonewtons
A hectonewton (hN) is equal to 100 newtons. It’s a relatively uncommon unit of force but can be useful when dealing with intermediate-scale forces that fall between kilonewtons and newtons. It might be used in measuring the force applied by certain mechanical devices.
{
"conversion": "petanewton-hectonewton",
"x_slug": "petanewton",
"y_slug": "hectonewton",
"x": "PT",
"y": "hN",
"x_desc": "Petanewtons",
"y_desc": "Hectonewtons",
"category": "Force",
"symbol": "m",
"formula": "x * 1e+13",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a planet exerting a force of 10 petanewtons on its moon.<br>Convert this force from petanewtons to Hectonewtons.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of planet in petanewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Petanewtons)</sub></span> = 10</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from petanewtons to hectonewtons is:</p>\n <p class=\"formula step\"><span>Force<sub>(Hectonewtons)</sub></span> = <span>Force<sub>(Petanewtons)</sub></span> × 1e+13</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of planet, <strong>Force<sub>(Petanewtons)</sub> = 10</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Hectonewtons)</sub></span> = <span>10</span> × 1e+13</p>\n <p class=\"step\"><span>Force<sub>(Hectonewtons)</sub></span> = 100000000000000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>10 PT</strong> is equal to <strong>100000000000000 hN</strong>.</p>\n <p>The force of planet is <strong>100000000000000 hN</strong>, in hectonewtons.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider the energy needed for interstellar travel requiring a force of 0.8 petanewtons.<br>Convert this force from petanewtons to Hectonewtons.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of interstellar vehicle required in petanewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Petanewtons)</sub></span> = 0.8</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from petanewtons to hectonewtons is:</p>\n <p class=\"formula step\"><span>Force<sub>(Hectonewtons)</sub></span> = <span>Force<sub>(Petanewtons)</sub></span> × 1e+13</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of interstellar vehicle required, <strong>Force<sub>(Petanewtons)</sub> = 0.8</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Hectonewtons)</sub></span> = <span>0.8</span> × 1e+13</p>\n <p class=\"step\"><span>Force<sub>(Hectonewtons)</sub></span> = 8000000000000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>0.8 PT</strong> is equal to <strong>8000000000000 hN</strong>.</p>\n <p>The force of interstellar vehicle required is <strong>8000000000000 hN</strong>, in hectonewtons.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"x_long_desc": "A petanewton (PT) is equal to 10<sup>15</sup> newtons. It’s an extremely large unit of force, mostly theoretical, used in astrophysics or high-energy physics to describe forces acting at a massive scale, such as between planets or in star formation.",
"y_long_desc": "A hectonewton (hN) is equal to 100 newtons. It’s a relatively uncommon unit of force but can be useful when dealing with intermediate-scale forces that fall between kilonewtons and newtons. It might be used in measuring the force applied by certain mechanical devices."
}