Use this free online force converter to change petanewtons into joules per meter instantly. Type in the petanewtons value, and the equivalent joules per meter is calculated for you in real time.
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Enter your inputs, and the result is calculated in real-time.
Petanewtons
Joules per Meter
How to use this Petanewtons to Joules per Meter Converter 🤔
Follow these steps to convert given Petanewtons value from Petanewtons units to Joules per Meter units.
Enter the input Petanewtons value in the text field.
The given Petanewtons is converted to Joules per Meter in realtime ⌚ using the formula, and displayed under the Joules per Meter label.
You may copy the resulting Joules per Meter value using the Copy button.
Formula
To convert given force from Petanewtons to Joules per Meter, use the following formula.
Joules per Meter = Petanewtons * 1e+15
Calculation
Calculation will be done after you enter a valid input.
Petanewtons
A petanewton (PT) is equal to 1015 newtons. It’s an extremely large unit of force, mostly theoretical, used in astrophysics or high-energy physics to describe forces acting at a massive scale, such as between planets or in star formation.
Joules per Meter
Joule per meter (J/m) is a unit that represents energy per unit length. It is often used in the context of surface tension, where it describes the energy required to increase the surface area of a liquid.
{
"conversion": "petanewton-joule-per-meter",
"x_slug": "petanewton",
"y_slug": "joule-per-meter",
"x": "PT",
"y": "J/m",
"x_desc": "Petanewtons",
"y_desc": "Joules per Meter",
"category": "Force",
"symbol": "m",
"formula": "x * 1e+15",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a planet exerting a force of 10 petanewtons on its moon.<br>Convert this force from petanewtons to Joules per Meter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of planet in petanewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Petanewtons)</sub></span> = 10</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from petanewtons to joules per meter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Meter)</sub></span> = <span>Force<sub>(Petanewtons)</sub></span> × 1e+15</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of planet, <strong>Force<sub>(Petanewtons)</sub> = 10</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = <span>10</span> × 1e+15</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = 10000000000000000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>10 PT</strong> is equal to <strong>10000000000000000 J/m</strong>.</p>\n <p>The force of planet is <strong>10000000000000000 J/m</strong>, in joules per meter.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider the energy needed for interstellar travel requiring a force of 0.8 petanewtons.<br>Convert this force from petanewtons to Joules per Meter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of interstellar vehicle required in petanewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Petanewtons)</sub></span> = 0.8</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from petanewtons to joules per meter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Meter)</sub></span> = <span>Force<sub>(Petanewtons)</sub></span> × 1e+15</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of interstellar vehicle required, <strong>Force<sub>(Petanewtons)</sub> = 0.8</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = <span>0.8</span> × 1e+15</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = 800000000000000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>0.8 PT</strong> is equal to <strong>800000000000000 J/m</strong>.</p>\n <p>The force of interstellar vehicle required is <strong>800000000000000 J/m</strong>, in joules per meter.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"x_long_desc": "A petanewton (PT) is equal to 10<sup>15</sup> newtons. It’s an extremely large unit of force, mostly theoretical, used in astrophysics or high-energy physics to describe forces acting at a massive scale, such as between planets or in star formation.",
"y_long_desc": "Joule per meter (J/m) is a unit that represents energy per unit length. It is often used in the context of surface tension, where it describes the energy required to increase the surface area of a liquid."
}