Use this free online force converter to change petanewtons into ounce-force instantly. Type in the petanewtons value, and the equivalent ounce-force is calculated for you in real time.
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Enter your inputs, and the result is calculated in real-time.
Petanewtons
Ounce-Force
How to use this Petanewtons to Ounce-Force Converter 🤔
Follow these steps to convert given Petanewtons value from Petanewtons units to Ounce-Force units.
Enter the input Petanewtons value in the text field.
The given Petanewtons is converted to Ounce-Force in realtime ⌚ using the formula, and displayed under the Ounce-Force label.
You may copy the resulting Ounce-Force value using the Copy button.
Formula
To convert given force from Petanewtons to Ounce-Force, use the following formula.
Ounce-Force = Petanewtons * 3.5969430896e+15
Calculation
Calculation will be done after you enter a valid input.
Petanewtons
A petanewton (PT) is equal to 1015 newtons. It’s an extremely large unit of force, mostly theoretical, used in astrophysics or high-energy physics to describe forces acting at a massive scale, such as between planets or in star formation.
Ounce-Force
Ounce-force (ozf) is the force exerted by gravity on a one-ounce mass. It is used for measuring smaller forces, often found in consumer products, such as the tension of a spring in a mechanical device.
{
"conversion": "petanewton-ounce-force",
"x_slug": "petanewton",
"y_slug": "ounce-force",
"x": "PT",
"y": "ozf",
"x_desc": "Petanewtons",
"y_desc": "Ounce-Force",
"category": "Force",
"symbol": "m",
"formula": "x * 3.5969430896e+15",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a planet exerting a force of 10 petanewtons on its moon.<br>Convert this force from petanewtons to Ounce-Force.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of planet in petanewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Petanewtons)</sub></span> = 10</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from petanewtons to ounce-force is:</p>\n <p class=\"formula step\"><span>Force<sub>(Ounce-Force)</sub></span> = <span>Force<sub>(Petanewtons)</sub></span> × 3.5969430896e+15</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of planet, <strong>Force<sub>(Petanewtons)</sub> = 10</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Ounce-Force)</sub></span> = <span>10</span> × 3.5969430896e+15</p>\n <p class=\"step\"><span>Force<sub>(Ounce-Force)</sub></span> = 35969430896000000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>10 PT</strong> is equal to <strong>35969430896000000 ozf</strong>.</p>\n <p>The force of planet is <strong>35969430896000000 ozf</strong>, in ounce-force.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider the energy needed for interstellar travel requiring a force of 0.8 petanewtons.<br>Convert this force from petanewtons to Ounce-Force.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of interstellar vehicle required in petanewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Petanewtons)</sub></span> = 0.8</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from petanewtons to ounce-force is:</p>\n <p class=\"formula step\"><span>Force<sub>(Ounce-Force)</sub></span> = <span>Force<sub>(Petanewtons)</sub></span> × 3.5969430896e+15</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of interstellar vehicle required, <strong>Force<sub>(Petanewtons)</sub> = 0.8</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Ounce-Force)</sub></span> = <span>0.8</span> × 3.5969430896e+15</p>\n <p class=\"step\"><span>Force<sub>(Ounce-Force)</sub></span> = 2877554471680000</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>0.8 PT</strong> is equal to <strong>2877554471680000 ozf</strong>.</p>\n <p>The force of interstellar vehicle required is <strong>2877554471680000 ozf</strong>, in ounce-force.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"x_long_desc": "A petanewton (PT) is equal to 10<sup>15</sup> newtons. It’s an extremely large unit of force, mostly theoretical, used in astrophysics or high-energy physics to describe forces acting at a massive scale, such as between planets or in star formation.",
"y_long_desc": "Ounce-force (ozf) is the force exerted by gravity on a one-ounce mass. It is used for measuring smaller forces, often found in consumer products, such as the tension of a spring in a mechanical device."
}