Convert Pound Foot per Square Second to Dekanewtons
Use this free online force converter to change pound foot per square second into dekanewtons instantly. Type in the pound foot per square second value, and the equivalent dekanewtons is calculated for you in real time.
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Pound Foot per Square Second
Dekanewtons
How to use this Pound Foot per Square Second to Dekanewtons Converter 🤔
Follow these steps to convert given Pound Foot per Square Second value from Pound Foot per Square Second units to Dekanewtons units.
Enter the input Pound Foot per Square Second value in the text field.
The given Pound Foot per Square Second is converted to Dekanewtons in realtime ⌚ using the formula, and displayed under the Dekanewtons label.
You may copy the resulting Dekanewtons value using the Copy button.
Formula
To convert given force from Pound Foot per Square Second to Dekanewtons, use the following formula.
Dekanewtons = Pound Foot per Square Second * 0.01382549543759999
Calculation
Calculation will be done after you enter a valid input.
Pound Foot per Square Second
Pound foot per square second is a unit used to describe force in the FPS system. It is sometimes used in older engineering contexts or for specialized calculations.
Dekanewtons
A dekanewton (daN) represents 10 newtons of force. It is a convenient unit for representing forces in contexts where newtons are too small, but kilonewtons are too large. Dekanewtons are occasionally used in mechanical and engineering applications.
{
"conversion": "pound-foot-per-square-second-dekanewton",
"x_slug": "pound-foot-per-square-second",
"y_slug": "dekanewton",
"x": "lbf·ft/s²",
"y": "daN",
"x_desc": "Pound Foot per Square Second",
"y_desc": "Dekanewtons",
"category": "Force",
"symbol": "m",
"formula": "x * 0.01382549543759999",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a system applying 250 pound-foot-per-square-second of force to rotate a wheel.<br>Convert this force from pound-foot-per-square-second to Dekanewtons.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of wheel in pound foot per square second is:</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = 250</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from pound foot per square second to dekanewtons is:</p>\n <p class=\"formula step\"><span>Force<sub>(Dekanewtons)</sub></span> = <span>Force<sub>(Pound Foot per Square Second)</sub></span> × 0.01382549543759999</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of wheel, <strong>Force<sub>(Pound Foot per Square Second)</sub> = 250</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Dekanewtons)</sub></span> = <span>250</span> × 0.01382549543759999</p>\n <p class=\"step\"><span>Force<sub>(Dekanewtons)</sub></span> = 3.4564</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>250 lbf·ft/s²</strong> is equal to <strong>3.4564 daN</strong>.</p>\n <p>The force of wheel is <strong>3.4564 daN</strong>, in dekanewtons.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a pendulum experiencing 100 pound-foot-per-square-second of force as it swings.<br>Convert this force from pound-foot-per-square-second to Dekanewtons.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of pendulum in pound foot per square second is:</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = 100</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from pound foot per square second to dekanewtons is:</p>\n <p class=\"formula step\"><span>Force<sub>(Dekanewtons)</sub></span> = <span>Force<sub>(Pound Foot per Square Second)</sub></span> × 0.01382549543759999</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of pendulum, <strong>Force<sub>(Pound Foot per Square Second)</sub> = 100</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Dekanewtons)</sub></span> = <span>100</span> × 0.01382549543759999</p>\n <p class=\"step\"><span>Force<sub>(Dekanewtons)</sub></span> = 1.3825</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>100 lbf·ft/s²</strong> is equal to <strong>1.3825 daN</strong>.</p>\n <p>The force of pendulum is <strong>1.3825 daN</strong>, in dekanewtons.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"y_long_desc": "A dekanewton (daN) represents 10 newtons of force. It is a convenient unit for representing forces in contexts where newtons are too small, but kilonewtons are too large. Dekanewtons are occasionally used in mechanical and engineering applications.",
"x_long_desc": "Pound foot per square second is a unit used to describe force in the FPS system. It is sometimes used in older engineering contexts or for specialized calculations."
}
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