Convert Pound Foot per Square Second to Kilogram-Force
Use this free online force converter to change pound foot per square second into kilogram-force instantly. Type in the pound foot per square second value, and the equivalent kilogram-force is calculated for you in real time.
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Enter your inputs, and the result is calculated in real-time.
Pound Foot per Square Second
Kilogram-Force
How to use this Pound Foot per Square Second to Kilogram-Force Converter 🤔
Follow these steps to convert given Pound Foot per Square Second value from Pound Foot per Square Second units to Kilogram-Force units.
Enter the input Pound Foot per Square Second value in the text field.
The given Pound Foot per Square Second is converted to Kilogram-Force in realtime ⌚ using the formula, and displayed under the Kilogram-Force label.
You may copy the resulting Kilogram-Force value using the Copy button.
Formula
To convert given force from Pound Foot per Square Second to Kilogram-Force, use the following formula.
Kilogram-Force = Pound Foot per Square Second * 0.014098081850172695
Calculation
Calculation will be done after you enter a valid input.
Pound Foot per Square Second
Pound foot per square second is a unit used to describe force in the FPS system. It is sometimes used in older engineering contexts or for specialized calculations.
Kilogram-Force
Kilogram-force (kgf) is the force exerted by the weight of one kilogram under standard gravity. It is often used in engineering to describe the force of everyday objects and loads, such as the force exerted by a heavy tool or piece of equipment. It is a non-SI unit but still finds practical use in many fields.
{
"conversion": "pound-foot-per-square-second-kilogram-force",
"x_slug": "pound-foot-per-square-second",
"y_slug": "kilogram-force",
"x": "lbf·ft/s²",
"y": "kgf",
"x_desc": "Pound Foot per Square Second",
"y_desc": "Kilogram-Force",
"category": "Force",
"symbol": "m",
"formula": "x * 0.014098081850172695",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a system applying 250 pound-foot-per-square-second of force to rotate a wheel.<br>Convert this force from pound-foot-per-square-second to Kilogram-Force.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of wheel in pound foot per square second is:</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = 250</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from pound foot per square second to kilogram-force is:</p>\n <p class=\"formula step\"><span>Force<sub>(Kilogram-Force)</sub></span> = <span>Force<sub>(Pound Foot per Square Second)</sub></span> × 0.014098081850172695</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of wheel, <strong>Force<sub>(Pound Foot per Square Second)</sub> = 250</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Kilogram-Force)</sub></span> = <span>250</span> × 0.014098081850172695</p>\n <p class=\"step\"><span>Force<sub>(Kilogram-Force)</sub></span> = 3.5245</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>250 lbf·ft/s²</strong> is equal to <strong>3.5245 kgf</strong>.</p>\n <p>The force of wheel is <strong>3.5245 kgf</strong>, in kilogram-force.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a pendulum experiencing 100 pound-foot-per-square-second of force as it swings.<br>Convert this force from pound-foot-per-square-second to Kilogram-Force.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of pendulum in pound foot per square second is:</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = 100</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from pound foot per square second to kilogram-force is:</p>\n <p class=\"formula step\"><span>Force<sub>(Kilogram-Force)</sub></span> = <span>Force<sub>(Pound Foot per Square Second)</sub></span> × 0.014098081850172695</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of pendulum, <strong>Force<sub>(Pound Foot per Square Second)</sub> = 100</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Kilogram-Force)</sub></span> = <span>100</span> × 0.014098081850172695</p>\n <p class=\"step\"><span>Force<sub>(Kilogram-Force)</sub></span> = 1.4098</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>100 lbf·ft/s²</strong> is equal to <strong>1.4098 kgf</strong>.</p>\n <p>The force of pendulum is <strong>1.4098 kgf</strong>, in kilogram-force.</p>\n </div>\n ",
"units": [
[
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"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
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[
"ton-force",
"Metric Ton-Force",
"tf"
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[
"exanewton",
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"EN"
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[
"petanewton",
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[
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[
"giganewton",
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[
"meganewton",
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[
"hectonewton",
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[
"dekanewton",
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[
"decinewton",
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"dN"
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[
"centinewton",
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"cN"
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[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
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[
"dyne",
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"dyn"
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[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
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[
"to-force-long",
"Long Ton-Force (UK)",
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[
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[
"kilopound-force",
"Kilopound-Force",
"kipf"
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[
"pound-force",
"Pound-Force",
"lbf"
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[
"ounce-force",
"Ounce-Force",
"ozf"
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[
"poundal",
"Poundals",
"pdl"
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[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
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"p"
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[
"kilopond",
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"kp"
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],
"y_long_desc": "Kilogram-force (kgf) is the force exerted by the weight of one kilogram under standard gravity. It is often used in engineering to describe the force of everyday objects and loads, such as the force exerted by a heavy tool or piece of equipment. It is a non-SI unit but still finds practical use in many fields.",
"x_long_desc": "Pound foot per square second is a unit used to describe force in the FPS system. It is sometimes used in older engineering contexts or for specialized calculations."
}
ConvertOnline