Convert Online Unit Length Rod to Astronomical Units
Convert Rod to Astronomical Units
Rod
rd ResetAstronomical Units
AU Copy
How to use this Rod to Astronomical Units Converter 🤔 Follow these steps to convert given Rod value from Rod units to Astronomical Units units.
Enter the input Rod value in the text field. The given Rod is converted to Astronomical Units in realtime ⌚ using the formula, and displayed under the Astronomical Units label. You may copy the resulting Astronomical Units value using the Copy button. Calculation Calculation will be done after you enter a valid input.
Rod to Astronomical Units Conversion TableThe following table gives some of the most used conversions from Rod to Astronomical Units.
Rod (rd ) Astronomical Units (AU ) 0 rd 0 AU 1 rd 3e-11 AU 2 rd 7e-11 AU 3 rd 1e-10 AU 4 rd 1.3e-10 AU 5 rd 1.7e-10 AU 6 rd 2e-10 AU 7 rd 2.4e-10 AU 8 rd 2.7e-10 AU 9 rd 3e-10 AU 10 rd 3.4e-10 AU 20 rd 6.7e-10 AU 50 rd 1.68e-9 AU 100 rd 3.36e-9 AU 1000 rd 3.362e-8 AU 10000 rd 3.3618e-7 AU 100000 rd 0.00000336181 AU
Rod A rod is a unit of length used in land measurement and surveying. One rod is equivalent to 16.5 feet or approximately 5.0292 meters.
The rod is defined as 16.5 feet, providing a measurement that is useful for various applications in land surveying, agriculture, and construction.
Rods are commonly used in tasks such as property measurement, plotting land, and agricultural practices. The unit provides a practical measurement for shorter distances and has historical significance in land surveying.
Astronomical Units An astronomical unit (AU) is a unit of length used in astronomy to measure distances within our solar system. One astronomical unit is equivalent to approximately 149,597,870.7 kilometers or about 92,955,807.3 miles.
The astronomical unit is defined as the mean distance between the Earth and the Sun.
Astronomical units are used to express distances between celestial bodies within the solar system, such as the distances between planets and their orbits. They provide a convenient scale for describing and comparing distances in a way that is more manageable than using kilometers or miles.
{
"conversion": "rods-astronomical_unit",
"x_slug": "rods",
"y_slug": "astronomical_unit",
"x": "rd",
"y": "AU",
"x_desc": "Rod",
"y_desc": "Astronomical Units",
"category": "Length",
"symbol": "m",
"formula": "x / 29745858326.177113",
"precision": 16,
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider that a boundary fence is 40 rods long.<br>Convert this length from rods to Astronomical Units.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The length in rod is:</p>\n <p class=\"step\"><span>Length<sub>(Rod)</sub></span> = 40</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert length from rod to astronomical units is:</p>\n <p class=\"formula step\"><span>Length<sub>(Astronomical Units)</sub></span> = <span>Length<sub>(Rod)</sub></span> / 29745858326.177113</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight <strong>Length<sub>(Rod)</sub> = 40</strong> in the above formula.</p>\n <p class=\"step\"><span>Length<sub>(Astronomical Units)</sub></span> = <span>40</span> / 29745858326.177113</p>\n <p class=\"step\"><span>Length<sub>(Astronomical Units)</sub></span> = 1.344725e-9</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>40 rd</strong> is equal to <strong>1.344725e-9 AU</strong>.</p>\n <p>The length is <strong>1.344725e-9 AU</strong>, in astronomical units.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider that a farmer marks a field boundary using 25 rods.<br>Convert this distance from rods to Astronomical Units.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The length in rod is:</p>\n <p class=\"step\"><span>Length<sub>(Rod)</sub></span> = 25</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert length from rod to astronomical units is:</p>\n <p class=\"formula step\"><span>Length<sub>(Astronomical Units)</sub></span> = <span>Length<sub>(Rod)</sub></span> / 29745858326.177113</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight <strong>Length<sub>(Rod)</sub> = 25</strong> in the above formula.</p>\n <p class=\"step\"><span>Length<sub>(Astronomical Units)</sub></span> = <span>25</span> / 29745858326.177113</p>\n <p class=\"step\"><span>Length<sub>(Astronomical Units)</sub></span> = 8.404531e-10</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>25 rd</strong> is equal to <strong>8.404531e-10 AU</strong>.</p>\n <p>The length is <strong>8.404531e-10 AU</strong>, in astronomical units.</p>\n </div>\n ",
"img": "<img class=\"conversion\" src=\"/images/unit/length/rods-astronomical_unit.webp\" height=\"360\" width=\"640\" alt=\"Rod to Astronomical Units Converter | rd to AU\" />",
"table1n": "<h2><span class=\"x\">Rod</span> to <span class=\"y\">Astronomical Units</span> Conversion Table</h2><p>The following table gives some of the most used conversions from Rod to Astronomical Units.</p><table><thead><tr><th scope=\"column\" role=\"columnheader\">Rod (<span class=\"unit\">rd</span>)</th><th scope=\"column\" role=\"columnheader\">Astronomical Units (<span class=\"unit\">AU</span>)</th><tr></thead><tbody><tr><td>0 <span class=\"unit\">rd</span></td><td>0 <span class=\"unit\">AU</span></td></tr><tr><td>1 <span class=\"unit\">rd</span></td><td>3e-11 <span class=\"unit\">AU</span></td></tr><tr><td>2 <span class=\"unit\">rd</span></td><td>7e-11 <span class=\"unit\">AU</span></td></tr><tr><td>3 <span class=\"unit\">rd</span></td><td>1e-10 <span class=\"unit\">AU</span></td></tr><tr><td>4 <span class=\"unit\">rd</span></td><td>1<span>.3e-10</span> <span class=\"unit\">AU</span></td></tr><tr><td>5 <span class=\"unit\">rd</span></td><td>1<span>.7e-10</span> <span class=\"unit\">AU</span></td></tr><tr><td>6 <span class=\"unit\">rd</span></td><td>2e-10 <span class=\"unit\">AU</span></td></tr><tr><td>7 <span class=\"unit\">rd</span></td><td>2<span>.4e-10</span> <span class=\"unit\">AU</span></td></tr><tr><td>8 <span class=\"unit\">rd</span></td><td>2<span>.7e-10</span> <span class=\"unit\">AU</span></td></tr><tr><td>9 <span class=\"unit\">rd</span></td><td>3e-10 <span class=\"unit\">AU</span></td></tr><tr><td>10 <span class=\"unit\">rd</span></td><td>3<span>.4e-10</span> <span class=\"unit\">AU</span></td></tr><tr><td>20 <span class=\"unit\">rd</span></td><td>6<span>.7e-10</span> <span class=\"unit\">AU</span></td></tr><tr><td>50 <span class=\"unit\">rd</span></td><td>1<span>.68e-9</span> <span class=\"unit\">AU</span></td></tr><tr><td>100 <span class=\"unit\">rd</span></td><td>3<span>.36e-9</span> <span class=\"unit\">AU</span></td></tr><tr><td>1000 <span class=\"unit\">rd</span></td><td>3<span>.362e-8</span> <span class=\"unit\">AU</span></td></tr><tr><td>10000 <span class=\"unit\">rd</span></td><td>3<span>.3618e-7</span> <span class=\"unit\">AU</span></td></tr><tr><td>100000 <span class=\"unit\">rd</span></td><td>0<span>.00000336181</span> <span class=\"unit\">AU</span></td></tr></table>",
"units": [
[
"meters",
"Meters",
"m"
],
[
"kilometers",
"Kilometers",
"km"
],
[
"decimeters",
"Decimeters",
"dm"
],
[
"centimeters",
"Centimeters",
"cm"
],
[
"millimeters",
"Millimeters",
"mm"
],
[
"micrometers",
"Micrometers",
"µm"
],
[
"nanometers",
"Nanometers",
"nm"
],
[
"miles",
"Miles",
"mi"
],
[
"yards",
"Yards",
"yd"
],
[
"feet",
"Feet",
"ft"
],
[
"inches",
"Inches",
"in"
],
[
"lightyears",
"Lightyears",
"ly"
],
[
"exameters",
"Exameters",
"Em"
],
[
"petameters",
"Petameters",
"Pm"
],
[
"terameters",
"Terameters",
"Tm"
],
[
"gigameters",
"Gigameters",
"Gm"
],
[
"megameters",
"Megameters",
"Mm"
],
[
"hectometers",
"Hectameters",
"hm"
],
[
"dekameters",
"Dekameters",
"dam"
],
[
"microns",
"Microns",
"µ"
],
[
"picometers",
"Picometers",
"pm"
],
[
"femtometers",
"Femtometers",
"fm"
],
[
"attometers",
"Attometers",
"am"
],
[
"megaparsecs",
"Megaparsecs",
"Mpc"
],
[
"kiloparsecs",
"Kiloparsecs",
"kpc"
],
[
"parsecs",
"Parsecs",
"pc"
],
[
"astronomical_unit",
"Astronomical Units",
"AU"
],
[
"leagues",
"Leagues",
"lea"
],
[
"nautical_leagues_uk",
"Nautical Leagues (UK)",
"nautical league"
],
[
"nautical_leagues",
"Nautical Leagues (International)",
"nautical league"
],
[
"leagues_statute",
"Leagues (statute)",
"st.league"
],
[
"nautical_miles_uk",
"Nautical Miles (UK)",
"NM (UK)"
],
[
"nautical_miles",
"Nautical miles (International)",
"nmi"
],
[
"miles_statute",
"Miles (statute)",
"mi (US)"
],
[
"miles_us_survey",
"Miles (US survey)",
"mi"
],
[
"miles_roman",
"Miles (Roman)",
"mi (roman)"
],
[
"kiloyards",
"Kiloyards",
"kyd"
],
[
"furlongs",
"Furlongs",
"fur"
],
[
"furlongs_us_survey",
"Furlongs (US survey)",
"fur"
],
[
"chains",
"Chains",
"ch"
],
[
"chain_us_survey",
"Chains (US survey)",
"ch"
],
[
"ropes",
"Ropes",
"rope"
],
[
"rods",
"Rod",
"rd"
],
[
"rods_us_survey",
"Rods (US survey)",
"rd"
],
[
"perch",
"Perch",
"perch"
],
[
"poles",
"Poles",
"pole"
],
[
"fathoms",
"Fathoms",
"fath"
],
[
"fathoms_us_survey",
"Fathoms (US survey)",
"fath"
],
[
"ell",
"ell",
"ell"
],
[
"foot_us_survey",
"Feet (US survey)",
"ft"
],
[
"links",
"Links",
"li"
],
[
"links_us_survey",
"link (US survey)",
"li"
],
[
"cubits_uk",
"Cubits (UK)",
"cubit"
],
[
"hands",
"Hands",
"hand"
],
[
"span_cloth",
"Span (cloth)",
"span"
],
[
"fingers_cloth",
"Fingers (cloth)",
"finger"
],
[
"nails",
"Nails (cloth)",
"nail"
],
[
"inches_us_survey",
"Inches (US survey)",
"in"
],
[
"barleycorns",
"Barleycorns",
"barleycorn"
],
[
"mil",
"mil",
"mil"
],
[
"microinches",
"Microinches",
"µin"
],
[
"angstroms",
"Angstroms",
"A"
],
[
"fermi",
"Fermi",
"f"
],
[
"arpents",
"Arpent",
"arpent"
],
[
"picas",
"Pica",
"pica"
],
[
"points",
"Point",
"point"
],
[
"twips",
"Twip",
"twip"
],
[
"aln",
"aln",
"aln"
],
[
"famns",
"Famns",
"famn"
],
[
"calibers",
"Caliber",
"cl"
],
[
"centiinches",
"Centiinch",
"cin"
],
[
"kens",
"Kens",
"ken"
],
[
"russian_archin",
"Russian archin",
"russian archin"
],
[
"roman_actus",
"Roman actus",
"Roman actus"
],
[
"vara_de_tarea",
"Vara De Tarea",
"vara de tarea"
],
[
"vara_conuquera",
"Vara Conuquera",
"vara conuquera"
],
[
"vara_castellana",
"vara Castellana",
"vara castellana"
],
[
"cubits_greek",
"Cubit (Greek)",
"cubit (Greek)"
],
[
"long_reeds",
"Long Reed",
"long reed"
],
[
"reeds",
"Reed",
"reed"
],
[
"long_cubits",
"Long cubits",
"long cubit"
],
[
"handbreadths",
"Handbreadth",
"handbreadth"
],
[
"fingerbreadth",
"Fingerbreadth",
"fingerbreadth"
],
[
"planck_length",
"Planck length",
"Planck length"
],
[
"electron_radius_classical",
"Electron radius (classical) ",
"electron radius"
],
[
"bohr_radius",
"Bohr radius",
"b"
],
[
"earths_equatorial_radius",
"Earth's equatorial radius",
"earth's equatorial radius"
],
[
"earths_polar_radius",
"Earth's polar radius",
"Earth's polar radius"
],
[
"earths_distance_from_sun",
"Earth's distance from sun",
"earth's distance from sun"
],
[
"suns_radius",
"Sun's radius",
"sun's radius"
]
],
"y_long_desc": "An astronomical unit (AU) is a unit of length used in astronomy to measure distances within our solar system. One astronomical unit is equivalent to approximately 149,597,870.7 kilometers or about 92,955,807.3 miles. </p><p>The astronomical unit is defined as the mean distance between the Earth and the Sun.</p><p>Astronomical units are used to express distances between celestial bodies within the solar system, such as the distances between planets and their orbits. They provide a convenient scale for describing and comparing distances in a way that is more manageable than using kilometers or miles.",
"x_long_desc": "A rod is a unit of length used in land measurement and surveying. One rod is equivalent to 16.5 feet or approximately 5.0292 meters. </p><p>The rod is defined as 16.5 feet, providing a measurement that is useful for various applications in land surveying, agriculture, and construction.</p><p>Rods are commonly used in tasks such as property measurement, plotting land, and agricultural practices. The unit provides a practical measurement for shorter distances and has historical significance in land surveying."
}