Use this free online force converter to change short ton-force into joules per centimeter instantly. Type in the short ton-force value, and the equivalent joules per centimeter is calculated for you in real time.
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Short Ton-Force
Joules per Centimeter
How to use this Short Ton-Force to Joules per Centimeter Converter 🤔
Follow these steps to convert given Short Ton-Force value from Short Ton-Force units to Joules per Centimeter units.
Enter the input Short Ton-Force value in the text field.
The given Short Ton-Force is converted to Joules per Centimeter in realtime ⌚ using the formula, and displayed under the Joules per Centimeter label.
You may copy the resulting Joules per Centimeter value using the Copy button.
Formula
To convert given force from Short Ton-Force to Joules per Centimeter, use the following formula.
Joules per Centimeter = Short Ton-Force * 8.896443230520623e+5
Calculation
Calculation will be done after you enter a valid input.
Short Ton-Force
Short ton-force represents the force exerted by the weight of a short ton (2,000 pounds) under standard gravity. It is used primarily in the United States to describe large forces in engineering, construction, and mechanics.
Joules per Centimeter
Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science.
{
"conversion": "ton-force-short-joule-per-centimeter",
"x_slug": "ton-force-short",
"y_slug": "joule-per-centimeter",
"x": "short tonf",
"y": "J/cm",
"x_desc": "Short Ton-Force",
"y_desc": "Joules per Centimeter",
"category": "Force",
"symbol": "m",
"formula": "x * 8.896443230520623e+5",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a crane lifting a load that requires 2 short ton-force.<br>Convert this force from short ton-force to Joules per Centimeter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of crane lifing a load in short ton-force is:</p>\n <p class=\"step\"><span>Force<sub>(Short Ton-Force)</sub></span> = 2</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from short ton-force to joules per centimeter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>Force<sub>(Short Ton-Force)</sub></span> × 8.896443230520623e+5</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of crane lifing a load, <strong>Force<sub>(Short Ton-Force)</sub> = 2</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>2</span> × 8.896443230520623e+5</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 1779288.6461</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>2 short tonf</strong> is equal to <strong>1779288.6461 J/cm</strong>.</p>\n <p>The force of crane lifing a load is <strong>1779288.6461 J/cm</strong>, in joules per centimeter.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a structure that can support a maximum of 5 short ton-force.<br>Convert this force from short ton-force to Joules per Centimeter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of structure in short ton-force is:</p>\n <p class=\"step\"><span>Force<sub>(Short Ton-Force)</sub></span> = 5</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from short ton-force to joules per centimeter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>Force<sub>(Short Ton-Force)</sub></span> × 8.896443230520623e+5</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of structure, <strong>Force<sub>(Short Ton-Force)</sub> = 5</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = <span>5</span> × 8.896443230520623e+5</p>\n <p class=\"step\"><span>Force<sub>(Joules per Centimeter)</sub></span> = 4448221.6153</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>5 short tonf</strong> is equal to <strong>4448221.6153 J/cm</strong>.</p>\n <p>The force of structure is <strong>4448221.6153 J/cm</strong>, in joules per centimeter.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"y_long_desc": "Joule per centimeter (J/cm) is similar to joule per meter but is used when a finer unit of measurement is needed. It is also used to describe surface energy and tension in materials science.",
"x_long_desc": "Short ton-force represents the force exerted by the weight of a short ton (2,000 pounds) under standard gravity. It is used primarily in the United States to describe large forces in engineering, construction, and mechanics."
}