Use this free online force converter to change short ton-force into joules per meter instantly. Type in the short ton-force value, and the equivalent joules per meter is calculated for you in real time.
to
Enter your inputs, and the result is calculated in real-time.
Short Ton-Force
Joules per Meter
How to use this Short Ton-Force to Joules per Meter Converter 🤔
Follow these steps to convert given Short Ton-Force value from Short Ton-Force units to Joules per Meter units.
Enter the input Short Ton-Force value in the text field.
The given Short Ton-Force is converted to Joules per Meter in realtime ⌚ using the formula, and displayed under the Joules per Meter label.
You may copy the resulting Joules per Meter value using the Copy button.
Formula
To convert given force from Short Ton-Force to Joules per Meter, use the following formula.
Joules per Meter = Short Ton-Force * 8.896443230520623e+3
Calculation
Calculation will be done after you enter a valid input.
Short Ton-Force
Short ton-force represents the force exerted by the weight of a short ton (2,000 pounds) under standard gravity. It is used primarily in the United States to describe large forces in engineering, construction, and mechanics.
Joules per Meter
Joule per meter (J/m) is a unit that represents energy per unit length. It is often used in the context of surface tension, where it describes the energy required to increase the surface area of a liquid.
{
"conversion": "ton-force-short-joule-per-meter",
"x_slug": "ton-force-short",
"y_slug": "joule-per-meter",
"x": "short tonf",
"y": "J/m",
"x_desc": "Short Ton-Force",
"y_desc": "Joules per Meter",
"category": "Force",
"symbol": "m",
"formula": "x * 8.896443230520623e+3",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a crane lifting a load that requires 2 short ton-force.<br>Convert this force from short ton-force to Joules per Meter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of crane lifing a load in short ton-force is:</p>\n <p class=\"step\"><span>Force<sub>(Short Ton-Force)</sub></span> = 2</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from short ton-force to joules per meter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Meter)</sub></span> = <span>Force<sub>(Short Ton-Force)</sub></span> × 8.896443230520623e+3</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of crane lifing a load, <strong>Force<sub>(Short Ton-Force)</sub> = 2</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = <span>2</span> × 8.896443230520623e+3</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = 17792.8865</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>2 short tonf</strong> is equal to <strong>17792.8865 J/m</strong>.</p>\n <p>The force of crane lifing a load is <strong>17792.8865 J/m</strong>, in joules per meter.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a structure that can support a maximum of 5 short ton-force.<br>Convert this force from short ton-force to Joules per Meter.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of structure in short ton-force is:</p>\n <p class=\"step\"><span>Force<sub>(Short Ton-Force)</sub></span> = 5</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from short ton-force to joules per meter is:</p>\n <p class=\"formula step\"><span>Force<sub>(Joules per Meter)</sub></span> = <span>Force<sub>(Short Ton-Force)</sub></span> × 8.896443230520623e+3</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of structure, <strong>Force<sub>(Short Ton-Force)</sub> = 5</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = <span>5</span> × 8.896443230520623e+3</p>\n <p class=\"step\"><span>Force<sub>(Joules per Meter)</sub></span> = 44482.2162</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>5 short tonf</strong> is equal to <strong>44482.2162 J/m</strong>.</p>\n <p>The force of structure is <strong>44482.2162 J/m</strong>, in joules per meter.</p>\n </div>\n ",
"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
"PT"
],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
"MN"
],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
"aN"
],
[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"y_long_desc": "Joule per meter (J/m) is a unit that represents energy per unit length. It is often used in the context of surface tension, where it describes the energy required to increase the surface area of a liquid.",
"x_long_desc": "Short ton-force represents the force exerted by the weight of a short ton (2,000 pounds) under standard gravity. It is used primarily in the United States to describe large forces in engineering, construction, and mechanics."
}