Petanewtons to Long Ton-Force (UK) Converter Enter Petanewtons
PT Long Ton-Force (UK)
tonf (UK) ⇅ Switch to Long Ton-Force (UK) to Petanewtons Converter How to use this Petanewtons to Long Ton-Force (UK) Converter 🤔 Follow these steps to convert given force from the units of Petanewtons to the units of Long Ton-Force (UK).
Enter the input Petanewtons value in the text field. The calculator converts the given Petanewtons into Long Ton-Force (UK) in realtime ⌚ using the conversion formula, and displays under the Long Ton-Force (UK) label. You do not need to click any button. If the input changes, Long Ton-Force (UK) value is re-calculated, just like that. You may copy the resulting Long Ton-Force (UK) value using the Copy button. To view a detailed step by step calculation of the conversion, click on the View Calculation button. You can also reset the input by clicking on Reset button present below the input field. Calculation Calculation will be done after you enter a valid input.
Examples
1
Consider a planet exerting a force of 10 petanewtons on its moon. Convert this force from petanewtons to Long Ton-Force (UK).
Answer:
Given:
The force of planet in petanewtons is:
Force(Petanewtons) = 10
Formula:
The formula to convert force from petanewtons to long ton-force (uk) is:
Force(Long Ton-Force (UK)) = Force(Petanewtons) × 1.003611353125e+11
Substitution:
Substitute given weight of planet, Force(Petanewtons) = 10 in the above formula.
Force(Long Ton-Force (UK)) = 10 × 1.003611353125e+11
Force(Long Ton-Force (UK)) = 1003611353125
Final Answer:
Therefore, 10 PT is equal to 1003611353125 tonf (UK) .
The force of planet is 1003611353125 tonf (UK) , in long ton-force (uk).
2
Consider the energy needed for interstellar travel requiring a force of 0.8 petanewtons. Convert this force from petanewtons to Long Ton-Force (UK).
Answer:
Given:
The force of interstellar vehicle required in petanewtons is:
Force(Petanewtons) = 0.8
Formula:
The formula to convert force from petanewtons to long ton-force (uk) is:
Force(Long Ton-Force (UK)) = Force(Petanewtons) × 1.003611353125e+11
Substitution:
Substitute given weight of interstellar vehicle required, Force(Petanewtons) = 0.8 in the above formula.
Force(Long Ton-Force (UK)) = 0.8 × 1.003611353125e+11
Force(Long Ton-Force (UK)) = 80288908250
Final Answer:
Therefore, 0.8 PT is equal to 80288908250 tonf (UK) .
The force of interstellar vehicle required is 80288908250 tonf (UK) , in long ton-force (uk).
{
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"x_slug": "petanewton",
"y_slug": "to-force-long",
"x": "PT",
"y": "tonf (UK)",
"x_desc": "Petanewtons",
"y_desc": "Long Ton-Force (UK)",
"category": "Force",
"symbol": "m",
"formula": "x * 1.003611353125e+11",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a planet exerting a force of 10 petanewtons on its moon.<br>Convert this force from petanewtons to Long Ton-Force (UK).</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of planet in petanewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Petanewtons)</sub></span> = 10</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from petanewtons to long ton-force (uk) is:</p>\n <p class=\"formula step\"><span>Force<sub>(Long Ton-Force (UK))</sub></span> = <span>Force<sub>(Petanewtons)</sub></span> × 1.003611353125e+11</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of planet, <strong>Force<sub>(Petanewtons)</sub> = 10</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Long Ton-Force (UK))</sub></span> = <span>10</span> × 1.003611353125e+11</p>\n <p class=\"step\"><span>Force<sub>(Long Ton-Force (UK))</sub></span> = 1003611353125</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>10 PT</strong> is equal to <strong>1003611353125 tonf (UK)</strong>.</p>\n <p>The force of planet is <strong>1003611353125 tonf (UK)</strong>, in long ton-force (uk).</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider the energy needed for interstellar travel requiring a force of 0.8 petanewtons.<br>Convert this force from petanewtons to Long Ton-Force (UK).</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of interstellar vehicle required in petanewtons is:</p>\n <p class=\"step\"><span>Force<sub>(Petanewtons)</sub></span> = 0.8</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from petanewtons to long ton-force (uk) is:</p>\n <p class=\"formula step\"><span>Force<sub>(Long Ton-Force (UK))</sub></span> = <span>Force<sub>(Petanewtons)</sub></span> × 1.003611353125e+11</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of interstellar vehicle required, <strong>Force<sub>(Petanewtons)</sub> = 0.8</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Long Ton-Force (UK))</sub></span> = <span>0.8</span> × 1.003611353125e+11</p>\n <p class=\"step\"><span>Force<sub>(Long Ton-Force (UK))</sub></span> = 80288908250</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>0.8 PT</strong> is equal to <strong>80288908250 tonf (UK)</strong>.</p>\n <p>The force of interstellar vehicle required is <strong>80288908250 tonf (UK)</strong>, in long ton-force (uk).</p>\n </div>\n ",
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"x_long_desc": "A petanewton (PT) is equal to 10<sup>15</sup> newtons. It’s an extremely large unit of force, mostly theoretical, used in astrophysics or high-energy physics to describe forces acting at a massive scale, such as between planets or in star formation."
}