How to use this Pound Foot per Square Second to Kilopound-Force Converter 🤔
Follow these steps to convert given force from the units of Pound Foot per Square Second to the units of Kilopound-Force.
Enter the input Pound Foot per Square Second value in the text field.
The calculator converts the given Pound Foot per Square Second into Kilopound-Force in realtime ⌚ using the conversion formula, and displays under the Kilopound-Force label. You do not need to click any button. If the input changes, Kilopound-Force value is re-calculated, just like that.
You may copy the resulting Kilopound-Force value using the Copy button.
To view a detailed step by step calculation of the conversion, click on the View Calculation button.
You can also reset the input by clicking on Reset button present below the input field.
What is the Formula to convert Pound Foot per Square Second to Kilopound-Force?
The formula to convert given force from Pound Foot per Square Second to Kilopound-Force is:
Force(Kilopound-Force) = Force(Pound Foot per Square Second) × 3.1080950171607255e-5
Substitute the given value of force in pound foot per square second, i.e., Force(Pound Foot per Square Second) in the above formula and simplify the right-hand side value. The resulting value is the force in kilopound-force, i.e., Force(Kilopound-Force).
Calculation
Calculation will be done after you enter a valid input.
Examples
1
Consider a system applying 250 pound-foot-per-square-second of force to rotate a wheel. Convert this force from pound-foot-per-square-second to Kilopound-Force.
Answer:
Given:
The force of wheel in pound foot per square second is:
Force(Pound Foot per Square Second) = 250
Formula:
The formula to convert force from pound foot per square second to kilopound-force is:
Force(Kilopound-Force) = Force(Pound Foot per Square Second) × 3.1080950171607255e-5
Substitution:
Substitute given weight of wheel, Force(Pound Foot per Square Second) = 250 in the above formula.
Therefore, 250 lbf·ft/s² is equal to 0.00777023754 kipf.
The force of wheel is 0.00777023754 kipf, in kilopound-force.
2
Consider a pendulum experiencing 100 pound-foot-per-square-second of force as it swings. Convert this force from pound-foot-per-square-second to Kilopound-Force.
Answer:
Given:
The force of pendulum in pound foot per square second is:
Force(Pound Foot per Square Second) = 100
Formula:
The formula to convert force from pound foot per square second to kilopound-force is:
Force(Kilopound-Force) = Force(Pound Foot per Square Second) × 3.1080950171607255e-5
Substitution:
Substitute given weight of pendulum, Force(Pound Foot per Square Second) = 100 in the above formula.
Therefore, 100 lbf·ft/s² is equal to 0.00310809502 kipf.
The force of pendulum is 0.00310809502 kipf, in kilopound-force.
Pound Foot per Square Second
Pound foot per square second is a unit used to describe force in the FPS system. It is sometimes used in older engineering contexts or for specialized calculations.
Kilopound-Force
Kilopound-force (kipf) is another term for kip-force, which represents 1,000 pounds of force. It is a unit frequently used in structural analysis and design in engineering to simplify large force calculations.
Frequently Asked Questions (FAQs)
1. What is the formula for converting Pound Foot per Square Second to Kilopound-Force in Force?
The formula to convert Pound Foot per Square Second to Kilopound-Force in Force is:
Pound Foot per Square Second * 3.1080950171607255e-5
2. Is this tool free or paid?
This Force conversion tool, which converts Pound Foot per Square Second to Kilopound-Force, is completely free to use.
3. How do I convert Force from Pound Foot per Square Second to Kilopound-Force?
To convert Force from Pound Foot per Square Second to Kilopound-Force, you can use the following formula:
Pound Foot per Square Second * 3.1080950171607255e-5
For example, if you have a value in Pound Foot per Square Second, you substitute that value in place of Pound Foot per Square Second in the above formula, and solve the mathematical expression to get the equivalent value in Kilopound-Force.
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"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a system applying 250 pound-foot-per-square-second of force to rotate a wheel.<br>Convert this force from pound-foot-per-square-second to Kilopound-Force.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of wheel in pound foot per square second is:</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = 250</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from pound foot per square second to kilopound-force is:</p>\n <p class=\"formula step\"><span>Force<sub>(Kilopound-Force)</sub></span> = <span>Force<sub>(Pound Foot per Square Second)</sub></span> × 3.1080950171607255e-5</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of wheel, <strong>Force<sub>(Pound Foot per Square Second)</sub> = 250</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Kilopound-Force)</sub></span> = <span>250</span> × 3.1080950171607255e-5</p>\n <p class=\"step\"><span>Force<sub>(Kilopound-Force)</sub></span> = 0.00777023754</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>250 lbf·ft/s²</strong> is equal to <strong>0.00777023754 kipf</strong>.</p>\n <p>The force of wheel is <strong>0.00777023754 kipf</strong>, in kilopound-force.</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a pendulum experiencing 100 pound-foot-per-square-second of force as it swings.<br>Convert this force from pound-foot-per-square-second to Kilopound-Force.</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of pendulum in pound foot per square second is:</p>\n <p class=\"step\"><span>Force<sub>(Pound Foot per Square Second)</sub></span> = 100</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from pound foot per square second to kilopound-force is:</p>\n <p class=\"formula step\"><span>Force<sub>(Kilopound-Force)</sub></span> = <span>Force<sub>(Pound Foot per Square Second)</sub></span> × 3.1080950171607255e-5</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of pendulum, <strong>Force<sub>(Pound Foot per Square Second)</sub> = 100</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Kilopound-Force)</sub></span> = <span>100</span> × 3.1080950171607255e-5</p>\n <p class=\"step\"><span>Force<sub>(Kilopound-Force)</sub></span> = 0.00310809502</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>100 lbf·ft/s²</strong> is equal to <strong>0.00310809502 kipf</strong>.</p>\n <p>The force of pendulum is <strong>0.00310809502 kipf</strong>, in kilopound-force.</p>\n </div>\n ",
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