How to use this Short Ton-Force to Long Ton-Force (UK) Converter 🤔
Follow these steps to convert given force from the units of Short Ton-Force to the units of Long Ton-Force (UK).
Enter the input Short Ton-Force value in the text field.
The calculator converts the given Short Ton-Force into Long Ton-Force (UK) in realtime ⌚ using the conversion formula, and displays under the Long Ton-Force (UK) label. You do not need to click any button. If the input changes, Long Ton-Force (UK) value is re-calculated, just like that.
You may copy the resulting Long Ton-Force (UK) value using the Copy button.
To view a detailed step by step calculation of the conversion, click on the View Calculation button.
You can also reset the input by clicking on Reset button present below the input field.
What is the Formula to convert Short Ton-Force to Long Ton-Force (UK)?
The formula to convert given force from Short Ton-Force to Long Ton-Force (UK) is:
Substitute the given value of force in short ton-force, i.e., Force(Short Ton-Force) in the above formula and simplify the right-hand side value. The resulting value is the force in long ton-force (uk), i.e., Force(Long Ton-Force (UK)).
Calculation
Calculation will be done after you enter a valid input.
Examples
1
Consider a crane lifting a load that requires 2 short ton-force. Convert this force from short ton-force to Long Ton-Force (UK).
Answer:
Given:
The force of crane lifing a load in short ton-force is:
Force(Short Ton-Force) = 2
Formula:
The formula to convert force from short ton-force to long ton-force (uk) is:
{
"conversion": "ton-force-short-to-force-long",
"x_slug": "ton-force-short",
"y_slug": "to-force-long",
"x": "short tonf",
"y": "tonf (UK)",
"x_desc": "Short Ton-Force",
"y_desc": "Long Ton-Force (UK)",
"category": "Force",
"symbol": "m",
"formula": "x * 0.8928571428582549",
"examples": "<div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">1</span>\n <h3 class=\"question\">Consider a crane lifting a load that requires 2 short ton-force.<br>Convert this force from short ton-force to Long Ton-Force (UK).</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of crane lifing a load in short ton-force is:</p>\n <p class=\"step\"><span>Force<sub>(Short Ton-Force)</sub></span> = 2</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from short ton-force to long ton-force (uk) is:</p>\n <p class=\"formula step\"><span>Force<sub>(Long Ton-Force (UK))</sub></span> = <span>Force<sub>(Short Ton-Force)</sub></span> × 0.8928571428582549</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of crane lifing a load, <strong>Force<sub>(Short Ton-Force)</sub> = 2</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Long Ton-Force (UK))</sub></span> = <span>2</span> × 0.8928571428582549</p>\n <p class=\"step\"><span>Force<sub>(Long Ton-Force (UK))</sub></span> = 1.7857</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>2 short tonf</strong> is equal to <strong>1.7857 tonf (UK)</strong>.</p>\n <p>The force of crane lifing a load is <strong>1.7857 tonf (UK)</strong>, in long ton-force (uk).</p>\n </div>\n <div class=\"example\">\n <div class=\"example_head\"><span class=\"example_n\">2</span>\n <h3 class=\"question\">Consider a structure that can support a maximum of 5 short ton-force.<br>Convert this force from short ton-force to Long Ton-Force (UK).</h3></div>\n <h4 class=\"answer\">Answer:</h4>\n <p><strong>Given:</strong></p>\n <p>The force of structure in short ton-force is:</p>\n <p class=\"step\"><span>Force<sub>(Short Ton-Force)</sub></span> = 5</p>\n <p><strong>Formula:</strong></p>\n <p>The formula to convert force from short ton-force to long ton-force (uk) is:</p>\n <p class=\"formula step\"><span>Force<sub>(Long Ton-Force (UK))</sub></span> = <span>Force<sub>(Short Ton-Force)</sub></span> × 0.8928571428582549</p>\n <p><strong>Substitution:</strong></p>\n <p>Substitute given weight of structure, <strong>Force<sub>(Short Ton-Force)</sub> = 5</strong> in the above formula.</p>\n <p class=\"step\"><span>Force<sub>(Long Ton-Force (UK))</sub></span> = <span>5</span> × 0.8928571428582549</p>\n <p class=\"step\"><span>Force<sub>(Long Ton-Force (UK))</sub></span> = 4.4643</p>\n <p><strong>Final Answer:</strong></p>\n <p>Therefore, <strong>5 short tonf</strong> is equal to <strong>4.4643 tonf (UK)</strong>.</p>\n <p>The force of structure is <strong>4.4643 tonf (UK)</strong>, in long ton-force (uk).</p>\n </div>\n ",
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"units": [
[
"newton",
"Newtons",
"N"
],
[
"kilonewton",
"Kilonewtons",
"kN"
],
[
"gram-force",
"Gram-Force",
"gf"
],
[
"kilogram-force",
"Kilogram-Force",
"kgf"
],
[
"ton-force",
"Metric Ton-Force",
"tf"
],
[
"exanewton",
"Exanewtons",
"EN"
],
[
"petanewton",
"Petanewtons",
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],
[
"teranewton",
"Teranewtons",
"TN"
],
[
"giganewton",
"Giganewtons",
"GN"
],
[
"meganewton",
"Meganewtons",
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],
[
"hectonewton",
"Hectonewtons",
"hN"
],
[
"dekanewton",
"Dekanewtons",
"daN"
],
[
"decinewton",
"Decinewtons",
"dN"
],
[
"centinewton",
"Centinewtons",
"cN"
],
[
"millinewton",
"Millinewtons",
"mN"
],
[
"micronewton",
"Micronewtons",
"µN"
],
[
"nanonewton",
"Nanonewtons",
"nN"
],
[
"piconewton",
"Piconewtons",
"pN"
],
[
"femtonewton",
"Femtonewtons",
"fN"
],
[
"attonewton",
"Attonewtons",
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[
"dyne",
"Dynes",
"dyn"
],
[
"joule-per-meter",
"Joules per Meter",
"J/m"
],
[
"joule-per-centimeter",
"Joules per Centimeter",
"J/cm"
],
[
"ton-force-short",
"Short Ton-Force",
"short tonf"
],
[
"to-force-long",
"Long Ton-Force (UK)",
"tonf (UK)"
],
[
"kip-force",
"Kip-Force",
"kipf"
],
[
"kilopound-force",
"Kilopound-Force",
"kipf"
],
[
"pound-force",
"Pound-Force",
"lbf"
],
[
"ounce-force",
"Ounce-Force",
"ozf"
],
[
"poundal",
"Poundals",
"pdl"
],
[
"pound-foot-per-square-second",
"Pound Foot per Square Second",
"lbf·ft/s²"
],
[
"pond",
"Ponds",
"p"
],
[
"kilopond",
"Kiloponds",
"kp"
]
],
"x_long_desc": "Short ton-force represents the force exerted by the weight of a short ton (2,000 pounds) under standard gravity. It is used primarily in the United States to describe large forces in engineering, construction, and mechanics."
}